所以我有一个像这样的php数组:
$myArray = array(
'name' => 'Series Name',
'data' => array(
array("2012-11-13",0.71),
array("2012-11-14",0.45),
array("2012-11-15",0.65),
array("2012-11-16",0.67),
)
);
我想以json_encoded格式输出这个数组,数组键作为对象名(?)。
当我echo json_encode
数组时,我得到了这个:
{
"name": "Series Name",
"data": [
[
"2012-11-13",
0.71
],
[
"2012-11-14",
0.45
],
[
"2012-11-15",
0.65
],
[
"2012-11-16",
0.67
]
]
}
这样做的问题是数组键(“name”和“data”)作为字符串输出。我需要他们成为对象。即没有他们周围的报价。
编辑: 目的是构建和使用带有highcharts的php数组。从this chart的来源中可以看出,数据以这种方式传递:
$(function () {
$('#container').highcharts({
chart: {
type: 'spline'
},
title: {
text: 'Snow depth in the Vikjafjellet mountain, Norway'
},
subtitle: {
text: 'An example of irregular time data in Highcharts JS'
},
xAxis: {
type: 'datetime',
dateTimeLabelFormats: { // don't display the dummy year
month: '%e. %b',
year: '%b'
}
},
yAxis: {
title: {
text: 'Snow depth (m)'
},
min: 0
},
tooltip: {
formatter: function() {
return '<b>'+ this.series.name +'</b><br/>'+
Highcharts.dateFormat('%e. %b', this.x) +': '+ this.y +' m';
}
},
series: [{
name: 'Winter 2007-2008',
// Define the data points. All series have a dummy year
// of 1970/71 in order to be compared on the same x axis. Note
// that in JavaScript, months start at 0 for January, 1 for February etc.
data: [
[Date.UTC(1970, 9, 27), 0 ],
[Date.UTC(1970, 10, 10), 0.6 ],
[Date.UTC(1970, 10, 18), 0.7 ],
[Date.UTC(1970, 11, 2), 0.8 ],
[Date.UTC(1970, 11, 9), 0.6 ],
[Date.UTC(1970, 11, 16), 0.6 ],
[Date.UTC(1970, 11, 28), 0.67],
[Date.UTC(1971, 0, 1), 0.81],
[Date.UTC(1971, 0, 8), 0.78],
[Date.UTC(1971, 0, 12), 0.98],
[Date.UTC(1971, 0, 27), 1.84],
[Date.UTC(1971, 1, 10), 1.80],
[Date.UTC(1971, 1, 18), 1.80],
[Date.UTC(1971, 1, 24), 1.92],
[Date.UTC(1971, 2, 4), 2.49],
[Date.UTC(1971, 2, 11), 2.79],
[Date.UTC(1971, 2, 15), 2.73],
[Date.UTC(1971, 2, 25), 2.61],
[Date.UTC(1971, 3, 2), 2.76],
[Date.UTC(1971, 3, 6), 2.82],
[Date.UTC(1971, 3, 13), 2.8 ],
[Date.UTC(1971, 4, 3), 2.1 ],
[Date.UTC(1971, 4, 26), 1.1 ],
[Date.UTC(1971, 5, 9), 0.25],
[Date.UTC(1971, 5, 12), 0 ]
]
}, {
name: 'Winter 2008-2009',
data: [
[Date.UTC(1970, 9, 18), 0 ],
[Date.UTC(1970, 9, 26), 0.2 ],
[Date.UTC(1970, 11, 1), 0.47],
[Date.UTC(1970, 11, 11), 0.55],
[Date.UTC(1970, 11, 25), 1.38],
[Date.UTC(1971, 0, 8), 1.38],
[Date.UTC(1971, 0, 15), 1.38],
[Date.UTC(1971, 1, 1), 1.38],
[Date.UTC(1971, 1, 8), 1.48],
[Date.UTC(1971, 1, 21), 1.5 ],
[Date.UTC(1971, 2, 12), 1.89],
[Date.UTC(1971, 2, 25), 2.0 ],
[Date.UTC(1971, 3, 4), 1.94],
[Date.UTC(1971, 3, 9), 1.91],
[Date.UTC(1971, 3, 13), 1.75],
[Date.UTC(1971, 3, 19), 1.6 ],
[Date.UTC(1971, 4, 25), 0.6 ],
[Date.UTC(1971, 4, 31), 0.35],
[Date.UTC(1971, 5, 7), 0 ]
]
}, {
name: 'Winter 2009-2010',
data: [
[Date.UTC(1970, 9, 9), 0 ],
[Date.UTC(1970, 9, 14), 0.15],
[Date.UTC(1970, 10, 28), 0.35],
[Date.UTC(1970, 11, 12), 0.46],
[Date.UTC(1971, 0, 1), 0.59],
[Date.UTC(1971, 0, 24), 0.58],
[Date.UTC(1971, 1, 1), 0.62],
[Date.UTC(1971, 1, 7), 0.65],
[Date.UTC(1971, 1, 23), 0.77],
[Date.UTC(1971, 2, 8), 0.77],
[Date.UTC(1971, 2, 14), 0.79],
[Date.UTC(1971, 2, 24), 0.86],
[Date.UTC(1971, 3, 4), 0.8 ],
[Date.UTC(1971, 3, 18), 0.94],
[Date.UTC(1971, 3, 24), 0.9 ],
[Date.UTC(1971, 4, 16), 0.39],
[Date.UTC(1971, 4, 21), 0 ]
]
}]
});
});
这是json还是形成javascript对象的另一种方式?
答案 0 :(得分:1)
假设您想在客户端使用JSON对象,对于浏览器支持JSON.parse();
,您可以使用JavaScript解析JSON字符串:
obj = JSON.parse(json);
哪个json
是从服务器传递的JSON字符串(PHP文件中json_encode($array);
的结果),但是为了浏览器兼容性,您可以使用jQuery:
obj = $.parseJSON(json);
答案 1 :(得分:-1)
使用stdClass
。
$obj = new stdClass();
$obj->name = "Series Name";
$obj->data = array(
array("2012-11-13",0.71),
array("2012-11-14",0.45),
array("2012-11-15",0.65),
array("2012-11-16",0.67),
);
echo json_encode($obj);
如果您不知道stdClass是什么,请查看this主题
编辑:为了让JSON生成有效代码,除数字代码外,所有键/值对都必须在引号内