我正在尝试使用ajax从php文件加载评论。
的index.php
<div id="commentsonpost" value="<?php echo $_GET['post'];?>">
</div>
<script type="text/javascript">
$(document).ready(function() {
var postid = $('#commentsonpost').attr("value");
alert(postid);
var dataString = 'getpostcomm=1&postid='+ postid;
$.ajax({
type: "get",
url: "getcomments.php",
data: dataString,
dataType:'html',
cache: false,
success: function(html){
alert("re");
$("#commentsonpost").append(html);
}
});
return false;
});
</script>
getcomments.php
if(isset($_GET['getpostcomm'])){
$var=$_GET['postid']; // Adding this line causing problems
$querycomm = "select U.fname,U.lname,U.usernick,C.bcommentid,C.comment,C.date,C.visible from blogcomments as C natural join users as U where C.visible=1 and U.visible=1 and C.bpostid='{$var}' ORDER BY C.date ASC";
$resultcomm = mysql_query ( $querycomm, $connection );
echo "<div id='pcomments'>";
while($commentonpost=mysql_fetch_array($resultcomm)){
if($commentonpost['visible']==1){
echo '
<div style="width:90%;float:left;margin-left:5%;margin-right:15%;margin-top:10px;" id="comment'.$commentonpost['commentid'].'">
<div style="width:10%;float:left;"><a href="profile.php?user='.$commentonpost['usernick'].'" >'.$commentonpost['fname']." ".$commentonpost['lname'].'</a></div>
<div style="width:78%;float:left;margin-left:2%;">'.$commentonpost['comment'].'</div>
<div style="width:8%;float:right;margin-left:2%;">
';
if($commentonpost['usernick']==$_SESSION['user_nick']){
echo ' <form action="" method="post">
<input type="submit" name="delcomm" value="X" class="delcombutton" id="'.$commentonpost['commentid'].'">
</form>
';
}
echo '<h5 class="msg">'.datetime($commentonpost['date']).'</h5>
</div>
<br/>
</div>
';
}
}
echo "</div>";
echo '
<form name = "form" method = "post" action="" onsubmit="return validateform()" style="width:100%">
<div style="width:90%;float:left;margin-left:5%;margin-right:15%;margin-top:10px;">
<div style="width:10%;float:left;"><a href="profile.php?user='.$_SESSION['user_nick'].'" >'.$_SESSION['user_fname']." ".$_SESSION['user_lname'].'</a></div>
<div style="width:78%;float:left;margin-left:2%;"><textarea placeholder="Comment..." name="commenttext" id="commenttext" class="inputcomment" ></textarea></div>
<br>
<input type="submit" id="'.$_POST['post'].'" name="SubmitComment" value="Comment " class="commentbutton" style="font-size:1em;width:100px;float:right;margin-top:4px;margin-right:9%;">
</div>
</form>
</div>
';
}
每当我在getcomments.php中添加$var=$_GET['postid'];
行时,ajax脚本就会停止工作。只要我从getcomments.php中删除$var=$_GET['postid'];
,就会正确显示查询部分(显然)表单。
有什么想法吗?
答案 0 :(得分:0)
在ajax更好地将数据字段设置为数组值:
$.ajax({
type: "get",
url: "getcomments.php",
data: {'getpostcomm':1,'postid':postid},
在你的PHP中,你必须清理你的Id ..(如果它的int你至少可以施放(int))......
$var = (int) $_GET['postid'];
另外在你的PHP添加检查是否isset($ _ GET ['postid'])...
if(isset($_GET['getpostcomm']) && isset($_GET['postid'])){
答案 1 :(得分:0)
var dataString = 'getpostcomm=1&postid='+ toString(postid);