Question

mydata = [{'date': datetime.datetime(2009, 1, 31, 0, 0), 'value': 14, 'year': u'2009'},
           {'date': datetime.datetime(2009, 2, 28, 0, 0), 'value': 84, 'year': u'2009'},
           {'date': datetime.datetime(2009, 3, 31, 0, 0), 'value': 77, 'year': u'2009'},
           {'date': datetime.datetime(2009, 4, 30, 0, 0), 'value': 80, 'year': u'2009'},
           {'date': datetime.datetime(2009, 5, 31, 0, 0), 'value': 6, 'year': u'2009'},
           {'date': datetime.datetime(2009, 6, 30, 0, 0), 'value': 16, 'year': u'2009'},
           {'date': datetime.datetime(2009, 7, 31, 0, 0), 'value': 16, 'year': u'2009'},
           {'date': datetime.datetime(2009, 8, 31, 0, 0), 'value': 1, 'year': u'2009'},
           {'date': datetime.datetime(2009, 9, 30, 0, 0), 'value': 9, 'year': u'2009'},
           {'date': datetime.datetime(2008, 1, 31, 0, 0), 'value': 77, 'year': u'2008'},
           {'date': datetime.datetime(2008, 2, 29, 0, 0), 'value': 60, 'year': u'2008'},
           {'date': datetime.datetime(2008, 3, 31, 0, 0), 'value': 28, 'year': u'2008'},
           {'date': datetime.datetime(2008, 4, 30, 0, 0), 'value': 9, 'year': u'2008'},
           {'date': datetime.datetime(2008, 5, 31, 0, 0), 'value': 74, 'year': u'2008'},
           {'date': datetime.datetime(2008, 6, 30, 0, 0), 'value': 70, 'year': u'2008'},
           {'date': datetime.datetime(2008, 7, 31, 0, 0), 'value': 75, 'year': u'2008'},
           {'date': datetime.datetime(2008, 8, 31, 0, 0), 'value': 7, 'year': u'2008'},
           {'date': datetime.datetime(2008, 9, 30, 0, 0), 'value': 10, 'year': u'2008'},
           {'date': datetime.datetime(2008, 10, 31, 0, 0), 'value': 54, 'year': u'2008'},
           {'date': datetime.datetime(2008, 11, 30, 0, 0), 'value': 55, 'year': u'2008'},
           {'date': datetime.datetime(2008, 12, 31, 0, 0), 'value': 40, 'year': u'2008'},
           {'date': datetime.datetime(2007, 12, 31, 0, 0), 'value': 93, 'year': u'2007'},]

在'mydata'中，我获得了连续月度数据列表。我写了一些代码来对它们进行分组。

partial_req_data = dict([(k,[f for f in v]) for k,v in itertools.groupby(mydata, key=lambda x : x.get('year'))])

现在我还需要一些有效的代码来填充{}的缺失月份，即空字典。有不好的方法，但我正在寻找好的方法。

required_data = {"2009": [{'date': datetime.datetime(2009, 1, 31, 0, 0), 'value': 14, 'year': u'2009' },
                  {'date': datetime.datetime(2009, 2, 28, 0, 0), 'value': 84, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 3, 31, 0, 0), 'value': 77, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 4, 30, 0, 0), 'value': 80, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 5, 31, 0, 0), 'value': 6, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 6, 30, 0, 0), 'value': 16, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 7, 31, 0, 0), 'value': 16, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 8, 31, 0, 0), 'value': 1, 'year': u'2009'},
                  {'date': datetime.datetime(2009, 9, 30, 0, 0), 'value': 9, 'year': u'2009'},
                  {}, {}, {}],

         "2008": [{'date': datetime.datetime(2008, 1, 31, 0, 0), 'value': 77, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 2, 29, 0, 0), 'value': 60, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 3, 31, 0, 0), 'value': 28, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 4, 30, 0, 0), 'value': 9, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 5, 31, 0, 0), 'value': 74, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 6, 30, 0, 0), 'value': 70, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 7, 31, 0, 0), 'value': 75, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 8, 31, 0, 0), 'value': 7, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 9, 30, 0, 0), 'value': 10, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 10, 31, 0, 0), 'value': 54, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 11, 30, 0, 0), 'value': 55, 'year': u'2008'},
                  {'date': datetime.datetime(2008, 12, 31, 0, 0), 'value': 40, 'year': u'2008'},]

         "2007": [{}, {}, {}, {}, {}, {}, {}, {}, {}, {}, {},
                  {'date': datetime.datetime(2007, 12, 31, 0, 0), 'value': 93, 'year': u'2007'}]
         }

Answer 1

import datetime
from itertools import groupby
from pprint import pprint

required_data={}
for k,g in groupby(mydata,key=lambda x: x.get('year')):
    partial={}
    for datum in g:
        partial[datum.get('date').month]=datum    
    required_data[k]=[partial.get(m,{}) for m in range(1,13)]
pprint(required_data)

对于每年k，partial是一个词典，其键是几个月。诀窍是使用partial.get(m,{})，因为这将在它存在时返回基准，或者在不存在时返回{}。

按年度分组数据

1 个答案: