拉入JSON值并添加到现有CSV中的新列

时间:2013-05-08 01:02:10

标签: php json csv

我正在尝试从JSON(下面)获取值并将它们插入到现有CSV的新列中。使用我当前的代码(也在下面),添加到新行的所有内容都是每行上的“Array”一词。如何调整代码以使其正常工作?另外,有没有办法为我正在创建的新列设置标题名称?

谢谢,请查看下面的代码,如果您有任何问题,请告诉我。

JSON blob:

{
 "test":{"12345":"98765","56789":"54321"},
 "control":{"99999":"987651","88888":"987652","22222":"987653","27644":"987655"}
}

当前CSV:

userid,foo_date,bar,baz,qux,country
"12345","2013-03-14","1.72500","1","1055.74","UK"
"38726","2013-03-14",\N,"1","3430.07","UK"
"85127","2013-03-14",\N,"0","635.25","US"
"16984","2013-03-14",\N,"1","5233.09","US"

当前PHP(根据How to add columns to CSV using PHP):

$json = json_decode($s, true);
$json_values = array_values($json['control']);

$newCsvData = array();

if (($handle = fopen("testgroup.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
        $data[] = $json_values;
        $newCsvData[] = $data;
    }
    fclose($handle);
}

$handle = fopen('testgroup.csv', 'w');

foreach ($newCsvData as $line) {
   fputcsv($handle, $line);
}

fclose($handle);

$s等于JSON blob。

生成的CSV应如下所示:

userid,foo_date,bar,baz,qux,country,extra
"12345","2013-03-14","1.72500","1","1055.74","UK","987651"
"38726","2013-03-14",\N,"1","3430.07","UK","987652"
"85127","2013-03-14",\N,"0","635.25","US","987653"
"16984","2013-03-14",\N,"1","5233.09","US","987655"

2 个答案:

答案 0 :(得分:2)

试试这个(测试过):

$data = <<<EOF
{
 "test":{"12345":"98765","56789":"54321"},
 "control":{"99999":"987651","88888":"987652","22222":"987653","27644":"987655"}
}
EOF;

$json = json_decode($data, true);
$json_values = array_values($json['control']);
// add column header to the start of the array
array_unshift($json_values, 'extra');

// open the file in read write mode.
$fd = fopen('testgroup.csv', 'r+');
// add the last field for each record
$records = array();
while($record = fgetcsv($fd)) {
    $record []= array_shift($json_values);
    $records []= $record;
}

// clear file and set seek to start
ftruncate($fd, 0); 
fseek($fd, 0); 

// rewrite file
foreach($records as $record) {
   fputcsv($fd, $record);
}

fclose($fd);

答案 1 :(得分:0)

另一种快速而天真的方法是:

$json = json_decode($s, true);
$json_values = array_values($json['control']);

$i = 0;
if (($handle = fopen("csvFile.csv", "r")) !== FALSE) {
    while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
       //seperate your header data
        $i++;
        if($i==1)
            $header = $data;
        else
            $datas[] = $data; //all the data
        $i++;
    }
    fclose($handle);
}

//adding the json now to the data based on the test value
// assuming that your json data length will be same as number of rows in csv
//you can modify the code easily to make it dynamic
$j=0;
foreach($datas as &$d){
    array_push($d, $json_values[$j]);
    $j++;       
}

//than append data in the file
$handle = fopen('testgroup.csv', 'r+');
//put the header inside the csv
fputcsv($handle, $header);

foreach ($datas as $line) {
   fputcsv($handle, $line);
}

fclose($handle);

这是你应该实现的第一种方法,一旦你能够找到一个更好的方法来实现这个,就像@ hek2mgl建议的那样..只是想把它扔出去......

DINS