Question

当我在构造函数中声明方法时，我收到错误“; expected”。不知道为什么。你能不能帮我理解

public class Reservation {
Date arrivalDate = new Date();
  Date departDate = new Date();
  Reservation(Date arrDate, Date deptDate)
   {
    arrivalDate = arrDate;
    departDate = deptDate;
    long nightsStay();
   }
 void nightsStay()
  {
      long days = (departDate.getTime()-arrivalDate.getTime())/(24*60*60*1000);
  }

我在我宣布长夜的线路上遇到错误Stay（）;

Answer 1

你做不到

long nightsStay();

如果您定义一个变量，您需要一个名称，然后您可以为其指定一个值，但您缺少该名称。

public class Reservation {
   Date arrivalDate = new Date();
   Date departDate = new Date();
   long nightsStay;  // add that line

   Reservation(Date arrDate, Date deptDate)
   {
      arrivalDate = arrDate;
      departDate = deptDate;
      nightsStay = nightsStay();  // change that line
    }

   long nightsStay()
   {
      long days = (departDate.getTime()-arrivalDate.getTime())/(24*60*60*1000);
   }
}

示例：

long l = 5;  //variable l gets value 5;
l = nightsStay();   // calling method nightsStay and storing the result in l;
long nightsStay(); // is neither one

如果您希望方法nightsStay()返回某些内容，则必须将返回类型从void更改为您要返回的类型，在您的情况下为long。< / p>

在构造函数中声明方法

1 个答案: