Question

我已经解决了这个问题：

SELECT round(avg(total_kpi),2) as avg_kpi, 
case when avg(total_kpi) < 3 then 'NEG' 
     when avg(total_kpi)>3 then 'POS' end  as kpi, 
count(gender) as gender,  
gender,  
round(avg(locacion),2) as avg_locacion, 
round(avg(tiempo),2) as avg_tiempo, 
round(avg(servicio),2) as avg_servicio, 
round(avg(calidad),2) as avg_calidad 
FROM datellig_ift.a02_view_kpi_2 
WHERE id_man_medicion=4 
group by 
case when avg(total_kpi) < 3 then 'NEG' 
     when avg(total_kpi) > 3 then 'POS' end

我需要按第2列对数据进行分组。分组时，mysql拒绝。
对不起，我一直在寻找一些帖子，但不明白为什么不工作。感谢。

错误讯息：

＃1111 - 无效使用群组功能

Answer 1

AVG()不能出现在GROUP BY子句中，因为它是“分组依据”或“聚合”功能。

有关所有聚合函数的详细信息，请参阅http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html。

根据您的跟进，我猜这个查询适合您：

SELECT
    IF(total_kpi < 3, 'NEG', 'POS') AS type,
    gender,  
    count(*) AS members,  
    round(avg(total_kpi),2) as avg_kpi, 
    round(avg(locacion),2) as avg_locacion, 
    round(avg(tiempo),2) as avg_tiempo, 
    round(avg(servicio),2) as avg_servicio, 
    round(avg(calidad),2) as avg_calidad 
FROM
    datellig_ift.a02_view_kpi_2 
WHERE
   id_man_medicion = 4 
GROUP BY
    total_kpi < 3, 
    gender

Answer 2

昨晚我终于找到了解决方案。由于我的评价很低，不允许回答我的问题。然而罗斯史密斯二世帮助我，并检查他提出的解决方案我发现它也工作正常。这是我做的：

SELECT count(total_kpi) as q_kpi, 
case when total_kpi < 3 then  'NEG'  when total_kpi>3 then  'POS'  end  as kpi, 
count(gender) as gender, 
gender, 
round(avg(locacion),2) as avg_locacion, 
round(avg(tiempo),2) as avg_tiempo, 
round(avg(servicio),2) as avg_servicio,
round(avg(calidad),2) as avg_calidad 
FROM datellig_ift.a02_view_kpi_2  where id_man_medicion=4 GROUP BY 2, 4

感谢罗斯史密斯，你的意见导致找到答案。

mysql group by summa列

2 个答案: