Question

我对此进行了编码，之前它正在运行！ alt + 1和alt + 2的全局热键。当我关闭我的项目时，我不小心按了一个键或者什么东西，现在由于某种原因只有alt + 1正在工作，而且没有alt +数字的其他组合......

    [DllImport("user32.dll")]
    public static extern bool RegisterHotKey(IntPtr hWnd, int id, int fsModifiers, int vlc);
    [DllImport("user32.dll")]
    public static extern bool UnregisterHotKey(IntPtr hWnd, int id);


    [DllImport("User32.dll")]
    private static extern short GetAsyncKeyState(System.Windows.Forms.Keys vKey);
    [DllImport("User32.dll")]
    private static extern short GetAsyncKeyState(System.Int32 vKey);
    const int MYACTION_HOTKEY_ID = 1;

    public Form1()
    {
        InitializeComponent();
        RegisterHotKey(this.Handle, MYACTION_HOTKEY_ID, 1, (int)Keys.D1);
        RegisterHotKey(this.Handle, MYACTION_HOTKEY_ID, 1, (int)Keys.D2);
    }

    protected override void WndProc(ref Message m)
    {

        if (m.Msg == 0x0312 && m.WParam.ToInt32() == MYACTION_HOTKEY_ID && (GetAsyncKeyState(Keys.D1) == -32767))
        {
            Console.Write("alt+1");
        }
        if (m.Msg == 0x0312 && m.WParam.ToInt32() == MYACTION_HOTKEY_ID && (GetAsyncKeyState(Keys.D2) == -32767))
        {
            Console.Write("alt+2");
        }
        base.WndProc(ref m);
    }

有人有什么想法吗？

Answer 1

RegisterHotkey（）的第二个参数是您指定组合的ID。每个组合都应该有自己的唯一ID（至少与关键组合关联的窗口句柄是唯一的）。当ID传递给WndProc（）中的m.WParam时，您可以确定按下了哪个热键。以下是alt-1的ID为1001，alt-2的ID为1002的示例：

public partial class Form1 : Form
{

    private const int WM_HOTKEY = 0x0312;
    private const int WM_DESTROY = 0x0002;

    [DllImport("user32.dll")]
    public static extern bool RegisterHotKey(IntPtr hWnd, int id, int fsModifiers, int vlc);
    [DllImport("user32.dll")]
    public static extern bool UnregisterHotKey(IntPtr hWnd, int id);

    public Form1()
    {
        InitializeComponent();
        RegisterHotKey(this.Handle, 1001, 1, (int)Keys.D1);
        RegisterHotKey(this.Handle, 1002, 1, (int)Keys.D2);
    }

    protected override void WndProc(ref Message m)
    {
        switch (m.Msg)
        {
            case WM_HOTKEY:
                switch (m.WParam.ToInt32())
                {
                    case 1001:
                        Console.Write("alt+1");
                        break;

                    case 1002:
                        Console.Write("alt+2");
                        break;

                }
                break;

            case WM_DESTROY:
                UnregisterHotKey(this.Handle, 1001);
                UnregisterHotKey(this.Handle, 1002);
                break;
        }
        base.WndProc(ref m);
    }

}

多个热键不使用alt +数字键

1 个答案: