在Java中计算生成的随机数中的最大和最小数字

时间:2013-05-07 21:57:41

标签: java random

所以我有一个Java程序,在0到9之间生成100个随机整数,我需要计算生成的整数的最大,最小和平均数。到目前为止我已经

import java.util.Random;

public class World {
    public static void main(String[] args) {

        public void generateNumber() {

            System.out.println("Generating 100 random integers between 0 and 9");

            Random aGenerator = new Random();

            int randomArray[]=new int[101];
            int countArray[]=new int[10];

            //generate the numbers and store into an array
            int j;
            for (int i=1; i<101; ++i) {
                j=i;
                randomArray[i]=aGenerator.nextInt(10);

                //displaying numbers
                System.out.println("Number " + j + " = " + randomArray[i]);
            }

            int max = randomArray[0];
            for (int i=1; i<randomArray.length; i++) {

                if (randomArray[i] > max) {
                    max =  randomArray[i];
                }
                System.out.println("Max number is "+ max);
            }
        }
    }
}

打印出来:

Generating 100 random integers between 0 and 9
Number 1 = 2
Number 2 = 9
Number 3 = 3
...
Number 99 = 4
Number 100 = 8

这是我想要的,但最大数字部分很奇怪。它打印出那条线很多次,我怎么做它只打印一次?

1 个答案:

答案 0 :(得分:1)

它打印的次数与for循环的次数相同,因为该语句在循环中。

你想要的是:

 int max = randomArray[0];
 for(int i=1; i<randomArray.length; i++) {
      if(randomArray[i] > max){
         max = randomArray[i];
       }
    }
  System.out.println("Max number is "+ max);