Question

请帮我创建一个Powershell脚本，该脚本将通过XML文件并更新内容。在下面的示例中，我想使用该脚本在Config.button.command示例中提取并更改文件路径。将C：\ Prog \ Laun.jar更改为C：\ Prog32 \ folder \ test.jar。请帮忙。感谢。

<config>
 <button>
  <name>Spring</name>
  <command>
     C:\sy32\java.exe -jar "C:\Prog\Laun.jar" YAHOO.COM --type SPNG --port 80
  </command>
  <desc>studies</desc>
 </button>
 <button>
  <name>JET</name>
    <command>
       C:\sy32\java.exe -jar "C:\Prog\Laun.jar" YAHOO.COM --type JET --port 80
    </command>
  <desc>school</desc>
 </button>
</config>

Answer 1

你有两个解决方案。您可以将其读作xml并替换文本，如下所示：

#using xml
$xml = [xml](Get-Content .\test.xml)
$xml.SelectNodes("//command") | % { 
    $_."#text" = $_."#text".Replace("C:\Prog\Laun.jar", "C:\Prog32\folder\test.jar") 
    }

$xml.Save("C:\Users\graimer\Desktop\test.xml")

或者你可以使用简单的字符串替换更简单，更快速，就像它是普通的文本文件一样。我会推荐这个。例如：

#using simple text replacement
$con = Get-Content .\test.xml
$con | % { $_.Replace("C:\Prog\Laun.jar", "C:\Prog32\folder\test.jar") } | Set-Content .\test.xml

Answer 2

我知道这是一个老帖子，但这可能对其他人有帮助......

如果您明确知道要查找的元素，那么您只需指定元素：

# Read the existing file
[xml]$xmlDoc = Get-Content $xmlFileName

# If it was one specific element you can just do like so:
$xmlDoc.config.button.command = "C:\Prog32\folder\test.jar"
# however this wont work since there are multiple elements

# Since there are multiple elements that need to be 
# changed use a foreach loop
foreach ($element in $xmlDoc.config.button)
{
    $element.command = "C:\Prog32\folder\test.jar"
}

# Then you can save that back to the xml file
$xmlDoc.Save("c:\savelocation.xml")

Answer 3

试试这个：

$xmlFileName = "c:\so.xml"
$match = "C:\\Prog\\Laun\.jar"
$replace = "C:\Prog32\folder\test.jar"


# Create a XML document
[xml]$xmlDoc = New-Object system.Xml.XmlDocument

# Read the existing file
[xml]$xmlDoc = Get-Content $xmlFileName

$buttons = $xmlDoc.config.button
$buttons | % { 
    "Processing: " + $_.name + " : " + $_.command
    $_.command = $_.command -Replace $match, $replace
    "Now: " + $_.command
    }

"Complete, saving"
$xmlDoc.Save($xmlFileName)

用于更新XML文件内容的Powershell脚本

3 个答案: