我只是想知道是否有人可以指出我正确的方向:我正在制作一个脚本,根据日期,我网站上的徽标会发生变化;所以例如很快就会出现haloween风格。
我开始时有2个数组,1个开始日期和1个结束日期(不确定即使这是最好的方法!):
<?php
$start_dates = array('01/01' => 'New Years',
'14/02' => 'Valentine Day',
'16/02/2010' => 'Pancake Day',
'17/03' => 'St Patricks Day',
'01/04' => 'April Fools',
'02/04/2010' => 'Easter',
'23/04' => 'St Georges Day',
'11/06/2010' => 'World Cup',
'31/10' => 'Halloween',
'05/11' => 'Guy Fawkes',
'11/11' => 'Armistice Day',
'16/10' => 'Today',
'15/12' => 'Christmas');
$end_dates = array( '08/01' => 'New Years',
'15/02' => 'Valentine Day',
'17/02/2010' => 'Pancake Day',
'18/03' => 'St Patricks Day',
'02/04' => 'April Fools',
'06/04/2010' => 'Easter',
'24/04' => 'St Georges Day',
'12/07/2010' => 'World Cup',
'01/11' => 'Halloween',
'06/11' => 'Guy Fawkes',
'12/11' => 'Armistice Day',
'17/10' => 'Today',
'01/01' => 'Christmas');
?>
到目前为止很容易...问题是,如果今天的日期介于开始日期和结束日期之间,那么我需要一种解决方法,然后更改图像文件名。
这是一个很长的镜头,但我希望有人能够提供帮助。
谢谢, 乙
答案 0 :(得分:0)
$events = array(
'New Year' => '01/01 01/08',
'Pancake Day' => '16/02/2010 17/02/2010',
//etc
);
echo find_event($events, '16/02');
其中find_event()是
function mdy2time($date) {
$e = explode('/', $date);
if(count($e) < 3)
$e[] = '2010';
return strtotime("$e[1]-$e[0]-$e[2]");
}
function find_event($events, $date = null) {
$date = is_null($date) ? time() : mdy2time($date);
foreach($events as $name => $range) {
list($start, $end) = explode(' ', $range);
if($date >= mdy2time($start) && $date <= mdy2time($end))
return $name;
}
return null;
}
答案 1 :(得分:0)
你应该使用更像这样的数组:
$dates = array();
$dates[] = array(
'name' => 'New Years'
'start' = '01/14',
'end' => '01/20',
'style' => 'haloween',
);
$dates[] = array(
//...
);
然后你可以得到如下风格:
$style='default';
// date as number e.g. 130 (january 30th)
$currDate = date('md',time()) * 1;
foreach ($dates AS $k => $v) {
$tmp = explode("/",$v['start'];
$start = ($tmp[1].$tmp[0])*1;
$tmp = explode("/",$v['end'];
$stop = ($tmp[1].$tmp[0])*1;
if ($start <= $currDate && $currDate < $stop) {
$style=$v['style'];
break;
}
}
echo 'style: '.$style;
尚未查看代码,如果错误,请随时纠正我。