Neo4j Rest使用Java调用(不是嵌入式模式)

时间:2013-05-07 16:32:02

标签: java rest post neo4j cypher

我实际上是在Neo4j中使用社区插件并尝试通过java发出POST请求来查询neo4j服务器。

我总是得到一个java.io.IOException:服务器返回HTTP响应代码:400 虽然类似的调用同一个url通过javascript工作,但业务逻辑建议通过java调用。

这是我的代码段:

String baseURL="ip_of_server";
    StringBuilder builder = new StringBuilder();
    try {
        URL url = new URL(baseURL);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        connection.setDoOutput(true);
        connection.setDoInput(true);
        connection.setRequestMethod("POST"); 
        connection.setRequestProperty("Content-Type", "application/json");
        OutputStream os=connection.getOutputStream();
         OutputStreamWriter writer = new OutputStreamWriter(os,Charset.forName("UTF-8"));


         System.out.println(url);
         Map<String, Object> params = new HashMap<String, Object>();
         params.put("query", "start x = node(3) return x");
         HashMap<String,String> test3= new HashMap<String,String>();
         params.put("params", test3);
         ObjectMapper temp = new ObjectMapper();

         String testString= temp.writeValueAsString(params);
         writer.write(testString);
         writer.close();
         os.close();


        String line = null;
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                connection.getInputStream()));
        while ((line = reader.readLine()) != null) {
            builder.append(line);

        }
        System.out.println("Response from server for request : " + url.toString() + " is " );
        System.out.println(builder.toString());



    } catch (Exception e) {
        // TODO: handle exception
        e.printStackTrace();
    }

有什么建议吗?

1 个答案:

答案 0 :(得分:0)

它需要的是解析器,因为'='等由编码转换为其他字符,因此neo4j会抛出错误