Question

我正在研究我的计算机编程原理入门课程的最后一个项目，我从一个旧项目中查找项目价格并将其转换为显示NFL团队的最终得分。

我的第一个有效的代码：

#Start Program

foundItemFlag = False
itemNum = (34, 124, 178, 219, 225) 
price = (3.76, 1.29, 4.78, 2.76, 4.51) 
input = int(input("Enter the Item Number: "))
for k in range (5):
    if input == itemNum[k]:
        foundItemFlag = True
        print("The item number you've chosen is ", input, "and the price is ", price[k])
if (foundItemFlag == False):
    print("Invalid Item Number!")

#End Program

这是我要修改的转换代码..

#Start Program

foundTeamFlag = False
teamName = ("Bills", "Dolphins", "Patriots", "Jets", "Ravens", "Bengals", "Browns", "Steelers", "Texans", "Colts", "Jaguars", "Titans", "Broncos", "Chiefs", "Raiders", "Chargers") 
final = (6-10, 7-9, "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9") 
input = int(input("To find your team's final record for last season please type in their name (Ravens, Texans and etc) :"))
for k in range (5):
    if input == teamName[k]:
        foundTeamFlag = True
        print("The ", input, "final record for 2012-2013 was ", final[k])
if (foundTeamFlag == False):
    print("Oops, check your team name and try again!")

#End Program

我非常喜欢初学者并将我的代码复制到IDLE中并收到NFL代码的错误：

SyntaxError: multiple statements found while compiling a single statement

Answer 1

我假设您使用的是Python 3.X？以下列出了您错误的事情：

将用户的输入（字符串）转换为int：这不起作用
将内置“输入”重新分配给变量名称
仅迭代变量“final”的前5个元素
正如另一个回答者所指出的，你可能想在你的“最终”元组中使用字符串

我会做如下的事情（对于python 3.x，将raw_input替换为input）：

foundTeamFlag = False
teamName = ("Bills", "Dolphins", "Patriots", "Jets", "Ravens", "Bengals", "Browns", "Steelers", "Texans", "Colts", "Jaguars", "Titans", "Broncos", "Chiefs", "Raiders", "Chargers") 
finalScores = ("6-10", "7-9", "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9") 
userInput = raw_input("To find your team's final record for last season please type in their name (Ravens, Texans and etc) :")
for name, score in zip(teamName, finalScores):
    if userInput == name:
        foundTeamFlag = True
        print("The ", userInput, "final record for 2012-2013 was ", score)
        break
if (foundTeamFlag == False):
    print("Oops, check your team name and try again!")

Answer 2

您对final的定义是一个问题：

final = (6-10, 7-9, "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9")

那里有减法陈述（前2）。将它们更改为字符串：

final = ("6-10", "7-9", "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9")

此外，请勿使用input，list，pass等名称作为变量名...

正如评论者指出的那样，不是主要评论者，

您要求用户输入团队名称，但要将其转换为整数..
你只是迭代元组的前5个元素......

您的最终代码应为：

foundTeamFlag = False
teamName = ("Bills", "Dolphins", "Patriots", "Jets", "Ravens", "Bengals", "Browns", "Steelers", "Texans", "Colts", "Jaguars", "Titans", "Broncos", "Chiefs", "Raiders", "Chargers") 
teams = ("6-10", "7-9", "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9") 
inp = input("To find your team's final record for last season please type in their name (Ravens, Texans and etc) : ")
for k in range(len(teams)):
    if inp == teamName[k]:
        foundTeamFlag = True
        print("The ", input, "final record for 2012-2013 was ", teams[k])
if (foundTeamFlag == False):
    print("Oops, check your team name and try again!")

但更灵活的方法是使用字典：

dic = {'Bengals': '10-6', 'Bills': '6-10', 'Broncos': '13-3','Browns': '5-11',
 'Chargers': '7-9', 'Chiefs': '2-14', 'Colts': '11-5', 'Dolphins': '7-9',
 'Jaguars': '2-14', 'Jets': '6-10', 'Patriots': '12-4', 'Raiders': '4-12',
 'Ravens': '10-6', 'Steelers': '8-8', 'Texans': '12-4', 'Titans': '6-10'}
name = input('Enter the name of the team you want the records of: ')
data = dic.get(name)
if data != None:
    print("The ", name, "final record for 2012-2013 was ", data)

Answer 3

您正在混合数据类型。例如，在final元组中有数字和字符串。此外，在您阅读输入的地方，您要求提供一个团队名称，这是一个字符串，但将其转换为int。对于初学者，试试这个：

foundTeamFlag = False
teamName = ("Bills", "Dolphins", "Patriots", "Jets", "Ravens", "Bengals", "Browns", "Steelers", "Texans", "Colts", "Jaguars", "Titans", "Broncos", "Chiefs", "Raiders", "Chargers")
final = ("6-10", "7-9", "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9")
inp = raw_input("To find your team's final record for last season please type in their name (Ravens, Texans and etc) : ")

for k in range(5):
    if inp == teamName[k]:
        foundTeamFlag = True
        print("The ", inp, "final record for 2012-2013 was ", final[k])
        break

if foundTeamFlag == False:
    print("Oops, check your team name and try again!")

现在，为了解决这个问题的更多Pythonic方法，抛弃循环并使用这样的字典：

teamName = ("Bills", "Dolphins", "Patriots", "Jets", "Ravens", "Bengals", "Browns", "Steelers", "Texans", "Colts", "Jaguars", "Titans", "Broncos", "Chiefs", "Raiders", "Chargers")
final = ("6-10", "7-9", "12-4", "6-10", "10-6", "10-6", "5-11", "8-8", "12-4", "11-5", "2-14", "6-10", "13-3", "2-14", "4-12", "7-9")
results = dict(zip(teamName, final))

inp = raw_input("To find your team's final record for last season please type in their name (Ravens, Texans and etc) : ")
if inp in results:
    print("The ", inp, "final record for 2012-2013 was ", results[inp])
else:
    print("Oops, check your team name and try again!")

我的Python代码出了什么问题？

3 个答案: