Question

我有两个活动，A和B.活动A通过广播接收器捕获意图，活动B触发它。

活动代码A：

final BroadcastReceiver mReceiver = new BroadcastReceiver() {
        public void onReceive(Context context, Intent intent) {

            String action = intent.getAction();         

            if(action.equals(floatyNetworkList.CONNECT_INTENT)){
                Log.v("com.vittorio", "intent catched");
                BluetoothDevice target = (BluetoothDevice) intent.getExtras().get("Device");
                Thread T = new Thread(new ConnectThread(target, mHandler, recmsgs, DDB, "Connecting"));
                T.start();
            }
..
..

在活动A中，我还使用以下代码注册接收器：

IntentFilter filter = new IntentFilter(BluetoothDevice.ACTION_FOUND);
filter.addAction(BluetoothAdapter.ACTION_DISCOVERY_FINISHED);
filter.addAction(floatyNetworkList.CONNECT_INTENT);
registerReceiver(mReceiver, filter);

活动代码B，当我从列表视图中选择一个项目时，我的意图被触发：

listBtview.setOnItemClickListener(new OnItemClickListener() {
    public void onItemClick(AdapterView<?> adapterBt, View myView, int myItemInt, long mylng) {

        @SuppressWarnings("unchecked")
        HashMap<String,String> selectedFromList =(HashMap<String,String>) (listBtview.getItemAtPosition(myItemInt));
        Toast.makeText(getBaseContext(), selectedFromList.get("Name"), Toast.LENGTH_LONG).show();

        Intent intent = new Intent(getApplicationContext(), Floaty.class);
        intent.setAction(CONNECT_INTENT);
        intent.putExtra("Device",fetchDevice(selectedFromList.get("Address")));
        getApplicationContext().sendBroadcast(intent);
      }                  
});

}

问题是活动A从未收到意图。我还为我的自定义意图添加了过滤器，并正确更新了我的清单。

清单代码：

    <intent-filter>
        <action android:name="android.intent.action.MAIN" />
        <category android:name="android.intent.category.LAUNCHER" />
        <action android:name="com.vittorio.intent.action.CONNECT_INTENT"/>
        <category android:name="android.intent.category.DEFAULT" />
    </intent-filter>

有什么想法吗？

谢谢

Answer 1

像这样创建意图：

Intent intent = new Intent();
intent.setAction(CONNECT_INTENT);

或

intent = new Intent(CONNECT_INTENT);

并且，是的，不要使用应用程序上下文，请在此站点上查看有关它的许多帖子

未收到自定义意图

1 个答案: