我
应用程序/ htaccess的
RewriteEngine on
RewriteCond $1 !^(index\.php|images|robots\.txt)
RewriteRule ^(.*)$ /index.php/$1 [L]
应用/配置/ routes.php文件
$route['default_controller'] = "news";
$route['404_override'] = '';
应用程序/模型/ news_model.php
<?php
class News_model extends CI_Model {
public function __construct()
{
$this->load->database();
}
public function get_news($slug = FALSE)
{
if ($slug === FALSE)
{
$query = $this->db->get('news');
return $query->result_array();
}
$query = $this->db->get_where('news', array('slug' => $slug));
return $query->row_array();
}
}
?>
应用程序/ controlers / news.php
<?php
class News extends CI_Controller {
public function __construct()
{
parent::__construct();
$this->load->model('news_model');
}
public function index()
{
$data['news'] = $this->news_model->get_news();
$data['title'] = 'News archive';
$this->load->view('templates/header', $data);
$this->load->view('news/index', $data);
$this->load->view('templates/footer');
}
public function view($slug)
{
echo $slug;
$data['news_item'] = $this->news_model->get_news($slug);
var_dump($data);
if (empty($data['news_item']))
{
show_404();
}
$data['title'] = $data['news_item']['title'];
$this->load->view('templates/header', $data);
$this->load->view('news/view', $data);
$this->load->view('templates/footer');
}
}
?>
应用程序/视图/ index.php的:
<?php foreach ($news as $news_item): ?>
<?php var_dump($news_item); ?>
<h2><?php echo "<pre>"; echo $news_item['title'] ?></h2>
<div id="main">
<?php echo $news_item['text'] ?>
</div>
<p><a href="news/<?php echo $news_item['slug'] ?>">View article</a></p>
<?php endforeach ?>
和Applications / views / view.php
<?php
echo '<h2>'.$news_item['title'].'</h2>';
echo $news_item['text'];
问题是我可以看到索引(列出我的新闻),但是当我点击一个slug链接时它会尝试转到:
/news/slug1
它触发了一个未找到的错误..
我在这里缺少什么?
答案 0 :(得分:3)
链接应该是:
<p><a href="/news/view/<?php echo $news_item['slug'] ?>">View article</a></p>
答案 1 :(得分:0)
Controller的索引方法应为:
public function index()
{
$data['news'] = $this->news_model->get_news();
$data['title'] = 'News archive';
$this->load->view('templates/header', $data);
$this->load->view('view', $data);
$this->load->view('templates/footer');
}
和文章链接必须是:
<p><a href="news/index/<?php echo $news_item['slug'] ?>">View article</a></p>
答案 2 :(得分:0)
假设您的CI位于/ demo文件夹中:
试试这个htaccess:
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteBase /demo/
#Needed for CodeIgniter
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond $1 !^(index\.php|pub|tmp|robots\.txt)
RewriteRule ^(.*)$ index.php/$1 [L]
</IfModule>
您的行动应该可以通过以下网址访问:
http://localhost:8080/demo/news/view/slug-here
和NOT
at:
http://localhost:8080/demo/news/slug-here