如何从<li>获得类<select> </select>

时间:2013-05-07 12:39:36

标签: jquery html-lists

如果里面有多个像这样的内容,你怎么从li获得这个类?

var ChooseAltType = $("<div>").appendTo(field_firstchild);

$('<div id="chooseCustomFields'
  + field_id
  + '" class="wrapper-customfields" tabindex="1"><span>Choose Type</span>'
  + '<ul id="chooseCustomField'
  + field_id
  + '" class="dropdown">'
  + '<li class="chooseCheckbox"><i class="fa-icon-check"></i>Checkbox</li>'
  + '<li class="chooseAlternatives"><i class="fa-icon-list-ul"></i> Alternatives</li>'
  + '<li class="chooseDropdown"><i class="fa-icon-list-alt"></i> Dropdown</li>'
  + '<li class="chooseTextField"><i class="fa-icon-font"></i> Text</li>'
  + '</ul></div>').appendTo(field_secondchild).addClass("metro three-d")
.click(function() {
    alert($('#chooseCustomFields' + field_id + ' ul #chooseCustomField'
            + field_id + ' li').prevAll().length);
});

这只是一段代码,但我希望它已经足够了!

2 个答案:

答案 0 :(得分:1)

这就是你能做的事情

   var class= $("li").attr('class'); // you can use your own Selector instead of $("li")

答案 1 :(得分:0)

尝试

var ChooseAltType = $("<div>").appendTo(field_firstchild);

$('<div id="chooseCustomFields'
  + field_id
  + '" class="wrapper-customfields" tabindex="1"><span>Choose Type</span>'
  + '<ul id="chooseCustomField'
  + field_id
  + '" class="dropdown">'
  + '<li class="chooseCheckbox"><i class="fa-icon-check"></i>Checkbox</li>'
  + '<li class="chooseAlternatives"><i class="fa-icon-list-ul"></i> Alternatives</li>'
  + '<li class="chooseDropdown"><i class="fa-icon-list-alt"></i> Dropdown</li>'
  + '<li class="chooseTextField"><i class="fa-icon-font"></i> Text</li>'
  + '</ul></div>').appendTo(field_secondchild).addClass("metro three-d")
.click(function() {
    $('#chooseCustomField' + field_id + ' li').each(function() {
        console.log($(this).attr('classs'))
    });
});