获取每种类型的总uid

Question

我需要找到有多少用户带来了产品（注意：我不需要用户总数，只需要有多少用户）。

表名：买家

+-----+----------+---------+
| id  | products |    uid  |
|-----|----------|---------|
| 1   |  soap    |    2    |
| 2   |  h_oil   |    1    |
| 3   |  soap    |    3    |
| 4   |  tea     |    1    |
| 5   |  soap    |    2    |
| 6   |  h_oil   |    1    |
| 7   |  soap    |    3    |
| 8   |  tea     |    1    |
+-----+----------+---------+

我需要如下表所示的结果：

|-----|---------------|--------------|
| id  | product_name  |  total_user  |
|-----|---------------|--------------|
| 1   |  soap         |      2       |
| 2   |  h_oil        |      1       |
| 3   |  tea          |      1       |
|------------------------------------|

如何在MySQL查询中执行此操作？

Answer 1

您可以使用：

SELECT product_name, COUNT(*) AS total_user FROM buyer GROUP BY product_name;

Answer 2

 SELECT products product_name, COUNT(DISTINCT uid) total_user FROM purchases GROUP BY products;

Answer 3

像这样：

SELECT 
    COUNT(*) 
FROM
    buyer
GROUP BY
    products 

Answer 4

简而言之，您正在寻找group by声明

SELECT uid, product_name, count(id) as total_user FROM buyer GROUP BY uid

在这里阅读更多内容：

• http://dev.mysql.com/doc/refman/5.0/en/group-by-functions.html

Answer 5

SELECT 
    COUNT(id) 
FROM
    buyer
GROUP BY
    products