在文件中,如果line包含substring,则从右侧获取所有行

时间:2013-05-07 09:01:18

标签: c# substring

我有一个档案。每一行如下所示:

[00000] 0xD176234F81150469: foo

我试图做的是,如果一行包含某个子字符串,我想提取找到的子字符串的 right 上的所有内容。例如,如果我在上面一行中搜索0xD176234F81150469:,它将返回foo。每个字符串的长度可变。我正在使用C#。

作为一个注释,文件中的每一行都如上所示,左边用方括号括起一个16号基数,后跟一个十六进制哈希和一个分号,然后是一个英文字符串。

我怎么能这样做?

修改

这是我的代码:

    private void button1_Click(object sender, EventArgs e)
    {
        Form1 box = new Form1();
        if(MessageBox.Show("This process may take a little while as we loop through all the books.", "Confirm?", MessageBoxButtons.YesNo, MessageBoxIcon.Information) == DialogResult.Yes)
        {
            XDocument doc = XDocument.Load(@"C:\Users\****\Desktop\books.xml");

            var Titles = doc.Descendants("Title");

            List<string> list = new List<string>();

            foreach(var Title in Titles)
            {
                string searchstr = Title.Parent.Name.ToString();
                string val = Title.Value;
                string has = @"Gameplay/Excel/Books/" + searchstr + @":" + val;
                ulong hash = FNV64.GetHash(has);
                var hash2 = string.Format("0x{0:X}", hash);

                list.Add(val + " (" + hash2 + ")");
                // Sample output: "foo (0xD176234F81150469)"
            }

            string[] books = list.ToArray();

            File.WriteAllLines(@"C:\Users\****\Desktop\books.txt", books);
        }
        else
        {
            MessageBox.Show("Aborted.", "Aborted");
        }
    }

我还遍历文件的每一行,将其添加到list<>。在尝试建议时,我一定是不小心删除了这个。另外,我对C#很新。我难以接受的主要是匹配。

4 个答案:

答案 0 :(得分:4)

您可以使用File.ReadLines和此Linq查询:

string search = "0xD176234F81150469:";
IEnumerable<String> lines = File.ReadLines(path)
    .Select(l => new { Line = l, Index = l.IndexOf(search) })
    .Where(x => x.Index > -1)
    .Select(x => x.Line.Substring(x.Index + search.Length));

foreach (var line in lines)
    Console.WriteLine("Line: " + line);

答案 1 :(得分:1)

如果您不想使用Linq查询,则此方法有效。

//"I also iterated through every line of the file, adding it to a list<>." Do this again.
List<string> li = new List<string>()

//However you create this string make sure you include the ":" at the end.
string searchStr = "0xD176234F81150469:"; 

private void button1_Click(object sender, EventArgs e)
{
    foreach (string line in li)
    {
        string[] words;
        words = line.Split(' '); //{"[00000]", "0xD176234F81150469:", "foo"}

        if (temp[1] == searchStr)
        {
            list.Add(temp[2] + " (" + temp[1] + ")");
            // Sample output: "foo (0xD176234F81150469)"
        }
    }
}

答案 2 :(得分:0)

string file = ...
string search= ...
var result = File.ReadLines(file)
              .Where(line => line.Contains(search))
              .Select(line => line.Substring(
                                   line.IndexOf(search) + search.Length + 1);

答案 3 :(得分:0)

不幸的是,没有其他解决方案适合我。我正在使用foreach迭代哈希,所以我将无数次地遍历所有项目数百万次。最后,我这样做了:

            using (StreamReader r = new StreamReader(@"C:\Users\****\Desktop\strings.txt"))
            {
                string line;
                while ((line = r.ReadLine()) != null)
                {
                    lines++;
                    if (lines >= 6)
                    {
                        string[] bits = line.Split(':');

                        if(string.IsNullOrWhiteSpace(line))
                        {
                            continue;
                        }

                        try
                        {
                            strlist.Add(bits[0].Substring(10), bits[1]);
                        }
                        catch (Exception)
                        {
                            continue;
                        }
                    }
                }
            }

            foreach(var Title in Titles)
            {
                string searchstr = Title.Parent.Name.ToString();
                string val = Title.Value;
                string has = @"Gameplay/Excel/Books/" + searchstr + ":" + val;
                ulong hash = FNV64.GetHash(has);
                var hash2 = " " + string.Format("0x{0:X}", hash);

                try
                {
                    if (strlist.ContainsKey(hash2))
                    {
                        list.Add(strlist[hash2]);
                    }
                }
                catch (ArgumentOutOfRangeException)
                {
                    continue;
                }
            }

这给了我在短时间内预期的输出。