我对MVC4编码很新。以前一直在SharePoint中编程。
我遇到的问题是我想将图像保存到特定文件夹(比如App_Data),并将图像的URL保存到数据库中的字符串。 如果有人能帮助我解决这个问题会很棒。
我现在得到的代码是。
模型> ImageUpload.cs
public class ImageUpload
{
public int ID { get; set; }
public string Title { get; set; }
public string Url { get; set; }
}
public class ImageUploadDBContext : DbContext
{
public DbSet<ImageUpload> ImageUploads { get; set; }
}
控制器&gt; ImageUploadController.cs
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create(ImageUpload imageupload)
{
if (ModelState.IsValid)
{
db.ImageUploads.Add(imageupload);
db.SaveChanges();
return RedirectToAction("Index");
}
return View(imageupload);
}
[HttpPost]
public ActionResult Upload(HttpPostedFileBase[] files)
{
foreach (HttpPostedFileBase file in files)
{
string picture = Path.GetFileName(file.FileName);
string path = Path.Combine(Server.MapPath("~/App_Data"), picture);
string[] paths = path.Split('.');
string time = DateTime.UtcNow.ToString();
time = time.Replace(" ", "-");
time = time.Replace(":", "-");
file.SaveAs(paths[0] + "-" + time + ".jpg");
}
ViewBag.Message = "File(s) uploaded successfully";
return RedirectToAction("Index");
}
查看&gt; ImageUpload&gt; Index.cshtml
@{
ViewBag.Title = "Index";
}
<h2>Index</h2>
<p>
@Html.ActionLink("Create New", "Create")
</p>
<table>
<tr>
<th>
@Html.DisplayNameFor(model => model.Title)
</th>
<th>
@Html.DisplayNameFor(model => model.Url)
</th>
<th>
Preview
</th>
<th></th>
</tr>
@foreach (var item in Model) {
<tr>
<td>
@Html.DisplayFor(modelItem => item.Title)
</td>
<td>
@Html.DisplayFor(modelItem => item.Url)
</td>
<td>
<img border="0" src="@Html.DisplayFor(modelItem => item.Url)" alt="@Html.DisplayFor(modelItem => item.Title)">
</td>
<td>
@Html.ActionLink("Edit", "Edit", new { id=item.ID }) |
@Html.ActionLink("Details", "Details", new { id=item.ID }) |
@Html.ActionLink("Delete", "Delete", new { id=item.ID })
</td>
</tr>
}
</table>
查看&gt; ImageUpload&gt; Create.cshtml
@{
ViewBag.Title = "Create";
}
<h2>Create</h2>
@using (Html.BeginForm()) {
@Html.AntiForgeryToken()
@Html.ValidationSummary(true)
<fieldset>
<legend>ImageUpload</legend>
@using (Html.BeginForm())
{
<div class="editor-label">
<b>@Html.LabelFor(Model => Model.Title)</b>
</div>
<div class="editor-field">
@Html.EditorFor(Model => Model.Title)
@Html.ValidationMessageFor(Model => Model.Title)
</div>
<div class="editor-label">
<b>@Html.LabelFor(Model => Model.Url)</b>
</div>
<div>
@Html.EditorFor(Model => Model.Url)
<input type="file" name="files" value="" multiple="multiple"/>
</div>
<div>
<input type="submit" value="Submit" />
</div>
}
</fieldset>
}
<div>
@Html.ActionLink("Back to List", "Index")
</div>
@section Scripts {
@Scripts.Render("~/bundles/jqueryval")
}
答案 0 :(得分:1)
对于文件上传,您可以使用此代码。保存到文件夹的图像和存储到数据库的文件名:
在控制器中:
[HttpPost]
public ActionResult Create(EventModel eventmodel, HttpPostedFileBase file)
{
if (ModelState.IsValid)
{
var filename = Path.GetFileName(file.FileName);
var path = Path.Combine(Server.MapPath("~/Uploads/Photo/"), filename);
file.SaveAs(path);
tyre.Url = filename;
_db.EventModels.AddObject(eventmodel);
_db.SaveChanges();
return RedirectToAction("Index");
}
return View(eventmodel);
}
观看:
<div>
Image
<input type="file" name="file" id="file" />
@Html.HiddenFor( model => model.ImageUrl)
@Html.ValidationMessageFor( model => model.Url )
</div>
答案 1 :(得分:0)
将两种方法合并为一种方法逻辑,代码应该是这样的:
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Upload(HttpPostedFileBase[] files)
{
// try to save the file
foreach (HttpPostedFileBase file in files)
{
string picture = Path.GetFileName(file.FileName);
string path = Path.Combine(Server.MapPath("~/App_Data"), picture);
string[] paths = path.Split('.');
string time = DateTime.UtcNow.ToString();
time = time.Replace(" ", "-");
time = time.Replace(":", "-");
file.SaveAs(paths[0] + "-" + time + ".jpg");
}
// try to save the new file name to db now.
try
{
db.ImageUploads.Add(paths[0] + time + ".jpg");
db.SaveChanges();
}
catch(Exception ex)
{
..........
}
ViewBag.Message = "File(s) uploaded successfully";
return RedirectToAction("Index");
}
答案 2 :(得分:0)
在您的控制器操作中,您需要执行HTTP请求以从远程服务器获取映像:
public ActionResult Thumb(int id)
{
using (var client = new WebClient())
{
byte[] image = client.DownloadData("http://cdn.foo.com/myimage.jpg");
return File(image, "image/jpg");
}
}
然后:
<img src="@Url.Action("Thumb")" alt="" />
显然现在图像被下载了两次。一旦从CDN进入控制器,一次从客户端进入。这完全违背了此控制器操作的目的,您可以直接引用CDN中的图像:
<img src="http://cdn.foo.com/myimage.jpg" alt="" />
这显然假设客户端可以访问CDN。
当然,如果您的控制器操作不仅仅是从CDN获取图像并将其流式传输到客户端,例如从CDN获取图像并调整其大小,那么您绝对应该采用第一种方法。