Question

这里我试图打印第一个和第二个wt ^及其对应的s ^到输出文件，剩下的wt ^和p ^应该打印到另一个输出文件。我怎么能这样做？

输入文件将是这样的

 wt^RHEL System Overview(contd..) 
            s^Supported architectures include:
            s^32-bit x86 compatible systems
            s^64-bit AMD64 (Opteron) and Intel EM64T systems


    wt^RHEL System Overview(contd..)        
                s^Common deployments        
                s^High volume deployments include:
                s^Corporate applications (CRM, ERP, etc.)
                s^Databases

    wt^RHEL System Overview(contd..)
            s^Network infrastructure systems
            s^Web serving
            s^File/print serving
            s^HPC compute systems

输出文件应该是这样的

output1.txt：

wt^RHEL System Overview(contd..) 
                s^Supported architectures include:
                s^32-bit x86 compatible systems
                s^64-bit AMD64 (Opteron) and Intel EM64T systems


        wt^RHEL System Overview(contd..)        
                    s^Common deployments        
                    s^High volume deployments include:
                    s^Corporate applications (CRM, ERP, etc.)
                    s^Databases

output2.txt：

wt^RHEL System Overview(contd..)
                s^Network infrastructure systems
                s^Web serving
                s^File/print serving
                s^HPC compute systems

我试过了

count=$(cat $( ls unit-*-slides.txt | sort -n ) | grep -E "[ ]*(st\^|p\^)" >> output.txt)

但这是印刷整个东西。

Answer 1

多年来我开始相信awk几乎可以做任何事情，（^是必要的吗？）

awk 'BEGIN {fout="file1";} /wt/{i++}i==3{fout="file2";} {print $0 > fout}' <filename>

如何将事件打印到文件

1 个答案: