Question

我正在尝试搜索solr，但我想优先搜索其他字段（如“Directors”）中的匹配字段（即Title）。这是我的schema.xml的一部分

<fields>
    <field name="Id" type="string" indexed="true" stored="true" required="true"/>
    <field name="Title" type="text_general" indexed="true" stored="true"/>
    <field name="OriginalTitle" type="text_general" indexed="true" stored="true"/>
    <field name="Directors" type="text_general" indexed="true" stored="true" multiValued="true" required="false"/>
    <field name="Language" type="text_general" indexed="false" stored="true" required="false"/>
    <field name="text" type="text_general" indexed="true" stored="false" multiValued="true"/>
</fields>

<uniqueKey>Id</uniqueKey>

<defaultSearchField>text</defaultSearchField> 

<solrQueryParser defaultOperator="OR"/> 

<copyField source="Title" dest="text"/>
<copyField source="OriginalTitle" dest="text"/>
<copyField source="Directors" dest="text"/>
<copyField source="Keywords" dest="text"/>

这是我的请求处理程序：

<lst name="responseHeader">
  <int name="status">0</int>
  <int name="QTime">2</int>
  <lst name="params">
    <str name="lowercaseOperators">true</str>
    <str name="pf">Title^100 Directors^10</str>
    <str name="indent">true</str>
    <str name="q">fo*</str>
    <str name="qf">Title Directors</str>
    <str name="stopwords">true</str>
    <str name="wt">xml</str>
    <str name="defType">edismax</str>
  </lst>
</lst>

我的结果是：

<result name="response" numFound="4" start="0">
  <doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Footloose</str>
    <arr name="Directors">
      <str>Herbert Ross</str>
    </arr>
    <str name="OriginalTitle">Footloose (1984)</str>
</doc>
  <doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Amadeus</str>
    <arr name="Directors">
      <str>Milos Forman</str>
    </arr>
    <str name="OriginalTitle">Amadeus</str>
</doc>
  <doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Forrest Gump</str>
    <arr name="Directors">
      <str>Robert Zemeckis</str>
    </arr>
    <str name="OriginalTitle">Forrest Gump</str>
</doc>
  <doc>
    <str name="Language">Doblado al español</str>
    <str name="Title">Chimpancés</str>
    <arr name="Directors">
      <str>Alastair Fothergill</str>
      <str> Mark Linfield</str>
    </arr>
    <str name="OriginalTitle">Chimpanzee Esp</str>
</doc>
</result>

但我想要这个结果：

<result name="response" numFound="4" start="0">
  <doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Footloose</str>
    <arr name="Directors">
      <str>Herbert Ross</str>
    </arr>
    <str name="OriginalTitle">Footloose (1984)</str>
</doc>
  <doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Forrest Gump</str>
    <arr name="Directors">
      <str>Robert Zemeckis</str>
    </arr>
    <str name="OriginalTitle">Forrest Gump</str>
</doc>
<doc>
    <str name="Language">Ingles subtítulos español</str>
    <str name="Title">Amadeus</str>
    <arr name="Directors">
      <str>Milos Forman</str>
    </arr>
    <str name="OriginalTitle">Amadeus</str>
</doc>
  <doc>
    <str name="Language">Doblado al español</str>
    <str name="Title">Chimpancés</str>
    <arr name="Directors">
      <str>Alastair Fothergill</str>
      <str> Mark Linfield</str>
    </arr>
    <str name="OriginalTitle">Chimpanzee Esp</str>
</doc>
</result>

我在查询中应该怎样做以获得我想要的响应？

更新：关于debug = True，我得到了这个结果：

<lst name="debug">
<str name="rawquerystring">fo*</str>
<str name="querystring">fo*</str>
<str name="parsedquery">
(+DisjunctionMaxQuery((Directors:fo* | Title:fo*)) () ())/no_coord
</str>
<str name="parsedquery_toString">+(Directors:fo* | Title:fo*) () ()</str>
<lst name="explain">
<str name="10">
1.0 = (MATCH) sum of: 1.0 = (MATCH) max of: 1.0 = (MATCH) ConstantScore(Title:fo*), product of: 1.0 = boost 1.0 = queryNorm
</str>
<str name="2">
1.0 = (MATCH) sum of: 1.0 = (MATCH) max of: 1.0 = (MATCH) ConstantScore(Directors:fo*), product of: 1.0 = boost 1.0 = queryNorm
</str>
<str name="12">
1.0 = (MATCH) sum of: 1.0 = (MATCH) max of: 1.0 = (MATCH) ConstantScore(Title:fo*), product of: 1.0 = boost 1.0 = queryNorm
</str>
<str name="711">
1.0 = (MATCH) sum of: 1.0 = (MATCH) max of: 1.0 = (MATCH) ConstantScore(Directors:fo*), product of: 1.0 = boost 1.0 = queryNorm
</str>
</lst>
<str name="QParser">ExtendedDismaxQParser</str>
<null name="altquerystring"/>
<null name="boost_queries"/>
<arr name="parsed_boost_queries"/>
<null name="boostfuncs"/>
<lst name="timing">
<double name="time">4.0</double>
<lst name="prepare">
<double name="time">1.0</double>
<lst name="query">
<double name="time">1.0</double>
</lst>
<lst name="facet">
<double name="time">0.0</double>
</lst>
<lst name="mlt">
<double name="time">0.0</double>
</lst>
<lst name="highlight">
<double name="time">0.0</double>
</lst>
<lst name="stats">
<double name="time">0.0</double>
</lst>
<lst name="debug">
<double name="time">0.0</double>
</lst>
</lst>
<lst name="process">
<double name="time">3.0</double>
<lst name="query">
<double name="time">0.0</double>
</lst>
<lst name="facet">
<double name="time">0.0</double>
</lst>
<lst name="mlt">
<double name="time">0.0</double>
</lst>
<lst name="highlight">
<double name="time">0.0</double>
</lst>
<lst name="stats">
<double name="time">0.0</double>
</lst>
<lst name="debug">
<double name="time">3.0</double>
</lst>
</lst>
</lst>
</lst>

Answer 1

您正在提升您的词组字段匹配，但不是您的查询字段匹配。你可能想要提高所有，特别是因为你的搜索实际上不是一个短语：

<str name="pf">Title^100 Directors^10</str>
<str name="qf">Title Directors</str>

尝试在 qf 字段上添加相同的权重。

Answer 2

你应该尝试做一个解释（但debug = true或debugQuery = trueto the querystring）来查看查询分数的哪些元素。看起来它可能是术语频率或这样的差别。由于你没有很多内容，它也可能在文档之间存在联系

Solr：领域的高优先级

2 个答案: