由于某种原因,这段代码片段无法正常工作。这应该做的是在i
小于colLength
时进行移动,此时为2意味着它应该在输入7后停止。并且由于某种原因它会一直持续到最后数组。
为什么要继续?我没有任何增加r
的代码?
//this is a 5 step process, this is the 4th
if (stepMaker == 4 && numLocation < totalSteps){
//looking through the array for the last number used in step 3, this works
for (int r = 0; r < gridRow-1; r++){
for (int c = 0; c < gridCol-1; c++){ // still looking
//using 5 instead of numLocation works, numLocation keeps going however... why?
if(grid[r][c] == (numLocation)) {
int x = 1;
for(int i = 0; i < colLength; i++){
grid[r + x][c] = numLocation + 1;
System.out.println("x=" + x + " // " +
"numLocation=" + numLocation + " // " +
"r=" + r + " // " +
"c=" + c + " // " +
"stepMaker=" + stepMaker + " // " +
"colLength=" + colLength + " // " +
"rowLength=" + rowLength);
numLocation++;
for (int xx = 0; xx < gridRow; xx++){
for (int yy = 0; yy < gridCol; yy++){
System.out.print(grid[xx][yy] + " ");
}
System.out.println("");
}
x++;
}
}
}
}
//colLength++;
stepMaker++;
}
这是输出:
x=1 // numLocation=5 // r=2 // c=2 // stepMaker=4 // colLength=2 // rowLength=3
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 5 4 3 0 0
0 0 6 1 2 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
x=2 // numLocation=6 // r=2 // c=2 // stepMaker=4 // colLength=2 // rowLength=3
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 5 4 3 0 0
0 0 6 1 2 0 0
0 0 7 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
x=1 // numLocation=7 // r=4 // c=2 // stepMaker=4 // colLength=2 // rowLength=3
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 5 4 3 0 0
0 0 6 1 2 0 0
0 0 7 0 0 0 0
0 0 8 0 0 0 0
0 0 0 0 0 0 0
x=2 // numLocation=8 // r=4 // c=2 // stepMaker=4 // colLength=2 // rowLength=3
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 5 4 3 0 0
0 0 6 1 2 0 0
0 0 7 0 0 0 0
0 0 8 0 0 0 0
0 0 9 0 0 0 0
rowLength = 3 // colLength = 2
答案 0 :(得分:0)
如果我理解正确的话,最后两个输出,其中添加了8和9是错误的。
问题是,你继续用更新的numLocation搜索网格,这个numLocation位于网格的一部分,没有搜索到。
解决方案是在找到numLocation并进行更改后打破外部循环(带有r和c的循环)。
为此,您需要在第一个之前添加标签:
label: for (int r = 0; r < gridRow-1; r++){...
并在最里面的for循环(使用i)之后插入
break label;