Question

我有两个字符串align_A和align_B有一些字符，如何打印align_A的第一行然后在下面（下一行）打印第一行{{1}然后在下面打印第二行align_B并在下一行打印第二行align_A，依此类推。我使用这样的代码插入可以在行中放置的字符（80个字符）。

align_B

我不写延续代码，因为我正在努力并没有准备好。这是复杂性，还有另一种方式（这样的功能）可以简单地执行这个动作吗？注意：字符串变量中没有行说明符，例如int len=align_A.length()/80; ...或\0。

Answer 1

使用std :: string。有了它，您可以使用find()查找下一个换行符。然后，您可以使用substr()拆分字符串。

#include <iostream>
#include <string>

int main(){
    std::string str = "aasdasdasda\nasdasdasd\nasdasdasd";

    int index = str.find('\n'); // Find position of newline
    std::cout << str.substr(0, index) << std::endl; // Print string until newline
    std::cout << str.substr(0, 10 ) << std::endl; // Print the first 80 charcters
}

Answer 2

我更喜欢char array和stdio：

#include <cstdio>
// #include <cstdlib>
#define SCREEN_SIZE_STR "80"

int main(){
    const char s1[] =
        "12345678901234567890123456789012345678901234567890123456789012345678901234567890"
        "12345678901234567890123456789012345678901234567890123456789012345678901234567890"
        "12345678901234567890123456789012345678901234567890123456789012345678901234567890"
        "12345678901234567890123456789012345678901234567890123456789012345678901234567890"
        "12345678901234567890123456789012345678901234567890123456789012345678901234567890";
    const char s2[] = 
        "abcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnop"
        "abcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnop"
        "abcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnop"
        "abcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnop"
        "abcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnopabcdefghijklmnop";

    int i1 = 0, i2 = 0;
    while(s1[i1] != '\0' && s2[i2] != '\0'){ // print both string
        i1 += printf("%."SCREEN_SIZE_STR"s", s1 + i1);
        i2 += printf("%."SCREEN_SIZE_STR"s", s2 + i2);
    }
    while(s1[i1] != '\0') // print the remaining of s1
        i1 += printf("%."SCREEN_SIZE_STR"s", s1 + i1);
    while(s2[i2] != '\0') // print the remaining of s2
        i2 += printf("%."SCREEN_SIZE_STR"s", s2 + i2);
    // system("pause");
    return 0;
}

如果您正在使用std::string：

const char *s1 = string1.c_str();
const char *s2 = string2.c_str();

在C ++中逐行打印两个字符串？

2 个答案: