Question

我有一个包含ManyToMany关系的模型：

@JoinTable(name = "Contract_has_Institution", joinColumns = { @JoinColumn(name = "contract_id", referencedColumnName = "id") }, inverseJoinColumns = { @JoinColumn(name = "institution_id", referencedColumnName = "id") })
@ManyToMany
public List<Institution> institutionCollection;

在scala.html中我有两个选择，在列表中添加两个元素（两个Insitutions）

    @select(contractForm("institutionCollection"),
         options = options(InstitutionController.options),
         '_default -> "--- Choose an institution ---",
         '_label -> "Institution A",
         '_showConstraints -> false)

    @select(contractForm("institutionCollection"),
         options = options(InstitutionController.options),
         '_default -> "--- Choose an institution ---",
         '_label -> "Institution B",
         '_showConstraints -> false)

我尝试将[]添加到这样的字段

 contractForm("institutionCollection[]"),

但它不起作用。如何将两个选定的选项绑定到列表中？

Answer 1

在您看来，如果您使用当前代码：

 @select(contractForm("institutionCollection"),
     options = options(InstitutionController.options),
     '_default -> "--- Choose an institution ---",
     '_label -> "Institution A",
     '_showConstraints -> false)

@select(contractForm("institutionCollection"),
     options = options(InstitutionController.options),
     '_default -> "--- Choose an institution ---",
     '_label -> "Institution B",
     '_showConstraints -> false)

因此，您可以使用此代码获取多次选择的值（这只是示例）：

public static Result someAction() {
    Map<String,String[]> formData = request().body().asFormUrlEncoded();

    Institution institution;
    // get all institutionCollection select value
    for (String insId : formData.get("institutionCollection")) {
        Logger.debug("INSTITUTION SELECTED = " + insId); // log info

        // I assume that select value is the ID of each Institution record
        institution = Institution.find.byId(Long.parseLong(insId))
        SomeModel.institutionCollection.add(institution) // add to the list to your model
    }
    SomeModel.save(); // save changes
    return ok("success");
}

Play Framework 2.0表单助手：从select到List <t> </t>

1 个答案: