Question

我有一个表单，用户可以使用该表单将文件上传到本地驱动器，并将一些数据保存到数据库中。但是这个错误信息出现了，我想知道如何处理它。

   HTTP Status 400 - The request sent by the client was syntactically incorrect.

控制器

@RequestMapping(value = "/main/user/setter/addpage", method = 

RequestMethod.POST, params = "save")
public String saveProcess(@ModelAttribute("module") Module module, 

@RequestParam("userId") Integer userId, 
@RequestParam("name") String name,
@RequestParam("file") MultipartFile file, 
BindingResult result, HttpSession session) {
    if (result.hasErrors()) {
        return "redirect:/main/user/setter/settingpage";
    }
    else
    if(module != null){

         try {

             MultipartFile filea = module.getFileData();

             InputStream inputStream = null;
             OutputStream outputStream = null;
             if (filea.getSize() > 0) {
             inputStream = filea.getInputStream();
             outputStream = new FileOutputStream("C:\\Test\\"
             + filea.getOriginalFilename());
             System.out.println("Uploaded File Name");
             System.out.println(filea.getOriginalFilename());
                             int readBytes = 0;
             byte[] buffer = new byte[8192];
             while ((readBytes = inputStream.read(buffer, 0, 8192)) != 

                             -1) {
             outputStream.write(buffer, 0, readBytes);
             }
             outputStream.close();
             inputStream.close();
             session.setAttribute("success", "File Uploaded");
             session.setAttribute("uploadFile", "C:\\Test\\"
             + filea.getOriginalFilename());
             }
             } catch (Exception e) {
             e.printStackTrace();
             }

}
// Delegate to service
moduleService.add(userId, module);

return "redirect:/main/user/setter/settingpage";
    }

表单本身

 <c:url var="processUrl" value="/main/user/setter/addpage?userId=2" />
 <form:form modelAttribute="module" method="POST" action="${processUrl}" name="module" 

 enctype="multipart/form-data">

 <form:label path="fileName">Document Title:</form:label>
 <form:input path="fileName" name="name"/><br/>

 <form:label path="documentPath">Coursework Sample:</form:label>
 <form:input path="documentPath" type="file" name="file" id="file" size="43.9"/><br/>

 <form:label path="liveDate">Live Date:</form:label>
 <form:input path="liveDate"/><br/>

  <input type="submit" name="save" value="Save" id="save"/>
  <input type="submit" name="send" value="Send" id="send"/>

 </form:form>

我正在尝试保存表单，我将使用单独的方法发送它。

Answer 1

您的方法声明如下：

public String saveProcess(@ModelAttribute("module") Module module, 
@RequestParam("userId") Integer userId, 
@RequestParam("name") String name,
@RequestParam("file") MultipartFile file, 
BindingResult result, HttpSession session) ...

假设您尝试将BindingResult应用于Module实例，则需要更改方法定义，以便在BindingResult实例之后找到Module

public String saveProcess(@ModelAttribute("module") Module module,  
BindingResult result,
@RequestParam("userId") Integer userId, 
@RequestParam("name") String name,
@RequestParam("file") MultipartFile file, 
HttpSession session) ...

有关详细信息，请参阅参考资料

错误或BindingResult参数必须遵循模型对象正如方法签名可能具有的那样立即绑定更多的是一个模型对象和Spring将创建一个单独的每个[...]
的BindingResult实例

见here。

Answer 2

错误HTTP Status 400 - The request sent by the client was syntactically incorrect.可能来自上下文中缺少的multipartResolver（servlet-context.xml）

`<beans:bean id="multipartResolver"
class="org.springframework.web.multipart.commons.CommonsMultipartResolver" />`

有关详情，请参阅SpringMVC-FileUpload - The request sent by the client was syntactically incorrect

的回复

Spring HTTP Status 400 - 客户端发送的请求在语法上不正确

2 个答案: