我真的没有一个很好的例子,主要是因为我只是扯着它,到目前为止,我的代码只是一个乱糟糟的混蛋 - dee哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇哇。我很茫然,需要一些帮助或建议。这就是我需要的:
我正在创建一个仅用于学习目的的模拟注册表单。我使用工作申请表作为我的例子。一页包含申请人的个人信息,如姓名,年龄,性别和教育程度。第二页允许他们选择他们希望申请的职位,并允许他们提供技能列表。我设置了一个model
来将data
和save
设置为database
。第一页将有一个ajax
下一个按钮,它将第一页表单替换为第二页表单。第二页有两个按钮,返回和提交(足够简单),也是ajax-y
。我现在的问题是从两个表单中将data
保存到entry
中的单个model
。有没有人有一个简单的例子或链接我可以考虑这种情况?或者甚至是另一种方式来解决这个问题?这将不胜感激!! :)
模型
public int Id { get; set; }
[Required(ErrorMessage = "First name Req")]
[Display(Name = "First name")]
public string First { get; set; }
[Required(ErrorMessage = "Last name Req")]
[Display(Name = "Last name")]
public string Last { get; set; }
[Required(ErrorMessage = "Age Req")]
[Range(18, 75, ErrorMessage = "Age Range of {1}-{2}")]
public int Age { get; set; }
[Required(ErrorMessage = "Please Select Gender")]
public string Gender { get; set; }
[Required(ErrorMessage = "Education Level Req")]
public string Education { get; set; }
public string Position { get; set; }
public string Skills { get; set; }
控制器
[HttpGet]
public PartialViewResult Apply1()
{
var model = db.Applications.Find(id);
if (model != null)
{
return PartialView("_Apply1", model);
}
return PartialView("_Apply1");
}
[HttpPost]
public PartialViewResult Apply1(Application app)
{
if (Request.IsAjaxRequest())
{
if (db.Applications.Where(a => a.First.ToLower() == app.First.ToLower() && a.Last.ToLower() == app.Last.ToLower() && a.Age == app.Age && a.Gender == app.Gender && a.Education == app.Education).Count() == 0)
{
app.Position = "x";
db.Applications.Add(app);
db.SaveChanges();
}
else
{
app = db.Applications.Single(a => a.First.ToLower() == app.First.ToLower() && a.Last.ToLower() == app.Last.ToLower() && a.Age == app.Age && a.Gender == app.Gender && a.Education == app.Education);
}
PosList(); //This is a helper Method, get's values for a dropdown list
id = app.Id;
var model = db.Applications.Find(id);
return PartialView("_Apply2", model);
}
return PartialView("_Apply1", app);
}
[HttpGet]
public PartialViewResult Apply2()
{
var model = db.Applications.Find(id);
if (model != null)
{
return PartialView("_Apply2", model);
}
return PartialView("_Apply2");
}
[HttpPost]
public PartialViewResult Apply2(Application app)
{
if (ModelState.IsValid)
{
db.Entry(app).State = EntityState.Modified;
db.SaveChanges();
ModelState.Clear();
return PartialView("_Success");
}
PosList();
return PartialView("_Apply2", app);
}
第一次观看
@model SiPrac.Models.Application
@using (Ajax.BeginForm("Apply1", new AjaxOptions()
{
InsertionMode = InsertionMode.Replace,
UpdateTargetId = "appForm"
}))
{
@Html.AntiForgeryToken()
<div class="editor-label">
@Html.LabelFor(model => model.First)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.First)
@Html.ValidationMessageFor(model => model.First)
</div>
<div class="clear"></div>
<div class="editor-label">
@Html.LabelFor(model => model.Last)
</div>
<div class="editor-field">
@Html.EditorFor(model => model.Last)
@Html.ValidationMessageFor(model => model.Last)
</div>
<div class="clear">
<input class="btn" type="submit" value="Next" />
}
第二次观看
@using (Ajax.BeginForm("Apply2", new AjaxOptions()
{
InsertionMode = InsertionMode.Replace,
UpdateTargetId = "appForm"
}))
{
@Html.AntiForgeryToken()
<div class="editor-label">
@Html.LabelFor(model => model.Position)
</div>
<div class="editor-field">
@Html.DropDownListFor(model => model.Position, (IEnumerable<SelectListItem>)ViewData["selectPos"])
</div>
<div class="clear"></div>
<input class="btn" type="submit" value="Submit" />
}
答案 0 :(得分:1)
好的,我会尝试让它尽可能短。因此,假设您已经知道如何在表单之间切换,我知道您根据您的问题进行切换,并且您有以下表单:
<form id="form1">
@Html.EditorFor(model => model.First)
// rest of the fields goes here
</form>
<form id="form2">
@Html.EditorFor(model => model.Position)
// rest of the fields goes here
<button id="submitAll">Submit</button>
</form>
假设您有按钮来回切换视图。 submitAll
按钮触发对控制器方法的回发操作,并传递如下值:
function submitAllFields() {
var o = {
// list properties here similar to your model property name
// and assign values to them
First: $("#First").val(),
Position: $("#Position").val()
};
$.post('@Url.Action("apply2")', { app: o }, function(result) {
// do something here
});
}
然后,您需要一种方法来接受所有输入:
[HttpPost]
public PartialViewResult Apply2(Application app)
{
if (ModelState.IsValid)
{
db.Entry(app).State = EntityState.Modified;
db.SaveChanges();
ModelState.Clear();
return PartialView("_Success");
}
// do something here
}