使用MySQL查询,我如何获取如示例A中的表:
Example A
+------+---------------+----------+
| id | value | class |
+------+---------------+----------+
| 1 | 33.00 | total |
| 1 | 12.00 | shipping |
| 2 | 45.00 | total |
| 2 | 15.00 | shipping |
+------+---------------+----------+
并创建一个类似于例B的视图?
Example B
+------+---------------+---------------+
| id | value_total | value_shipping|
+------+---------------+---------------+
| 1 | 33.00 | 12.00 |
| 2 | 45.00 | 15.00 |
+------+---------------+---------------+
答案 0 :(得分:0)
试试这个
select id ,
max(case when class = 'total' then value end) as value_total
, max(case when class = 'shipping' then value end) as value_shipping
from Table1
group by id
答案 1 :(得分:0)
您只需使用SUM()
功能:
SELECT id
,SUM(CASE WHEN class = 'total' THEN value ELSE 0 END) AS value_total
,SUM(CASE WHEN class = 'shipping' THEN value ELSE 0 END) AS value_shipping
FROM Table1
GROUP BY id;
如果您的 class 数量未知,请尝试此动态查询
SET @sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(case when class = ''',
class,
''' then value else 0 end) AS `value_',
class, '`'
)
) INTO @sql
FROM Table1;
SET @sql = CONCAT('SELECT id, ', @sql, '
FROM Table1
GROUP BY id');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
输出:
╔════╦═════════════╦════════════════╗
║ ID ║ VALUE_TOTAL ║ VALUE_SHIPPING ║
╠════╬═════════════╬════════════════╣
║ 1 ║ 33 ║ 12 ║
║ 2 ║ 45 ║ 15 ║
╚════╩═════════════╩════════════════╝