用户通过8个JTextField输入他的信息。此信息通过参数传递到updateUser方法,该方法使用此信息更新SQL表。这是我目前正在尝试做的事情,尽管当用户按下更新按钮时,不会对数据库表进行任何更改
检索用户数据,创建UserOperation并调用updateUser方法
String userName = textFieldUserName.getText();
String userPassword = textField_1.getText();
String securityQuestion = textFieldSecQuestion.getText();
String securityAnswer = textFieldAnswer.getText();
String email = textFieldEmail.getText();
String fName = textFieldName.getText();
String phoneNumber = textFieldPhone.getText();
String department = textFieldDepartment.getText();
UserOperations userOperations = new UserOperations();
userOperations.updateUser(userName, userPassword, securityQuestion, securityAnswer, email, fName, phoneNumber, department);
updateUser方法
public void updateUser (String userName, String userPassword, String securityQuestion, String securityAnswer, String email, String fName, String phoneNumber, String department)
{
try
{
String sql = "UPDATE systeuser SET username = ?,userpassword = ?,securityquestion = ?,securityanswer = ?,email = ?,fname = ?,phonenumber = ?,department = ? WHERE username = ?";
stmt = conn.prepareStatement(sql);
stmt.setString (1, userName);
stmt.setString (2, userPassword);
stmt.setString (3, securityQuestion);
stmt.setString (4, securityAnswer);
stmt.setString (5, email);
stmt.setString (6, fName);
stmt.setString (7, phoneNumber);
stmt.setString (8, department);
stmt.setString (9, userName);
stmt.executeUpdate( );
}
catch (Exception e)
{
e.printStackTrace ( );
}
}
答案 0 :(得分:3)
因为?
周围放置了单引号。你不需要给出那些单引号,因为你这样做: -
stmt.setString(1, userName); // setString says that this parameter is a String
因此,在您的情况下,不需要通常用于在查询中包含String
的单引号。
答案 1 :(得分:0)
不要将问号用于引号中的查询参数。相反,使用:
UPDATE systeuser SET username = ?, userpassword = ?, ...