我正在尝试使用“QextSerialPort”打开我的Huwawei USB加密狗。
我的PORT详情如下
Port Name:
Product ID:
Physical Name: \Device\000000ca
Vendor Id:
Friend Name: SB
Port Name:
Product ID:?
Physical Name: \Device\USBPDO-10
Vendor Id: ?
Friend Name: TH
Port Name: COM3
Product ID:
Physical Name: \Device\BthModem0
Vendor Id:
Friend Name: Standard Serial over Bluetooth link (COM3)
Port Name: COM4
Product ID:
Physical Name: \Device\BthModem2
Vendor Id:
Friend Name: Standard Serial over Bluetooth link (COM4)
Port Name: COM5
Product ID:
Physical Name: \Device\BthModem1
Vendor Id:
Friend Name: Standard Modem over Bluetooth link
Port Name: COM6
Product ID:?
Physical Name: \Device\000000e2
Vendor Id: ?
Friend Name: HUAWEI Mobile Connect - 3G Application Interface (COM6)
Port Name: COM7
Product ID:?
Physical Name: \Device\000000e0
Vendor Id: ?
Friend Name: HUAWEI Mobile Connect - 3G Modem
Port Name: COM8
Product ID:?
Physical Name: \Device\000000e3
Vendor Id: ?
Friend Name: HUAWEI Mobile Connect - 3G PC UI Interface (COM8)
我试图打开我的USB加密狗,所以我可以发送短信。以下是我打开的代码
#include "MyClass.h"
#include <qstring.h>
#include <qdebug.h>
int main()
{
QextSerialPort *port = new QextSerialPort("COM7");
port->open(QIODevice::ReadWrite);
cout << port->isOpen();
system("pause");
return 0;
}
当我运行此代码时,我得到的是
QWinEventNotifier: Can only be used with threads started with QThread
1
这显示端口ID已打开,但该消息呢?这是否意味着我无法继续使用其他代码?在我编写任何其他内容之前,我想知道这一点。请帮忙!
答案 0 :(得分:3)
最有可能的是,你需要创建一个QApplication
,没有它,事件和信号/插槽等很多东西都不会起作用:
int main()
{
QApplication app;
QextSerialPort *port = new QextSerialPort("COM7");
port->open(QIODevice::ReadWrite);
cout << port->isOpen();
system("pause");
return app.exec();
}