Question

我有两个请求一个接一个地开始。像这样的起始请求

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.google.com"]];
NSURLRequest *request = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringLocalCacheData timeoutInterval:60];
NSURLConnection * connection = [[NSURLConnection alloc]
                                initWithRequest:request
                                delegate:self startImmediately:NO];
[connection scheduleInRunLoop:[NSRunLoop mainRunLoop]
                      forMode:NSDefaultRunLoopMode];
[connection start];

和另一个这样的请求。

NSURL *url1 = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.apple.com"]];
NSURLRequest *request1 = [NSURLRequest requestWithURL:url1 cachePolicy:NSURLRequestReloadIgnoringLocalCacheData timeoutInterval:60];
NSURLConnection *connection1 = [[NSURLConnection alloc] initWithRequest:request1 delegate:self];
[connection1 release];

如何在委托方法中区分这两者？

-(void)connectionDidFinishLoading:(NSURLConnection *)connection{}

不想为此目的保留任何额外的类变量。

Answer 1

很简单：

-(void)connectionDidFinishLoading:(NSURLConnection *)connection
{
     if (connection == connection1)
     {
         //It's for connection1.
     }
     else if (connection == connection2)
     {
         //It's for connection2.
     }
}

你可以通过这个美丽的SO问题：Managing multiple asynchronous NSURLConnection connections

Answer 2

将你的NSURLConnection个对象放在.h文件中，并按照Markus的建议检查你的委托方法。

或

对您的NSURLConnection进行子类化，然后您可以在创建时将tag属性添加到连接类，在委派方法中检查适当的标记。您可以找到working tutorial here。

区分委托中的NSURLConnection对象

2 个答案: