Question

我不太清楚如何做到这一点。假设我有2个关联数组

$arr1 = array('a' => "1", 'b' => "2", 'c' => "3");
$arr2 = array('a' => "9", 'b' => "8", 'c' => "7");

我怎么可能产生一个“加总”数组，如下所示

$arr1 = array(
  array('a', "1", "9"),
  array('b', "2", "8"),
  array('c', "3", "7")
);

我不确定上面的语法是否正确。如果不是，那么看起来像下面的加起来也会这样做

$arr1 = array(
  'a' => array("1", "9"),
  'b' => array("2", "8"),
  'c' => array("3", "7")
);

由于

Answer 1

foreach($arr1 as $k=>$v) {
    $new[$k] = array($v, $arr2[$k]);
}

我认为你想要什么。但如果我弄错了，你可以这样做：

foreach($arr1 as $k=>$v) {
    $new[] = array($k, $v, $arr2[$k]);
}

Answer 2

$arr1 = array('a' => "1", 'b' => "2", 'c' => "3");
$arr2 = array('a' => "9", 'b' => "8", 'c' => "7");

$summ=array();
foreach(array($arr1,$arr2) as $arr){
    $keys=array_keys($arr);
    foreach($keys as $key){
        if(isset($summ[$key]))
            $summ[$key][]=$arr[$key];
        else $summ[$key]=array($arr[$key];
    }
}
/*
This will have made:
$sum = array(  
    'a' => array("1", "9"),  
    'b' => array("2", "8"),  
    'c' => array("3", "7")
);

I leave it up to you to now reduce this one more step to match your desired output.
*/

在PHP中合并多个关联数组

2 个答案: