Question

我有两个这样的案例类。

case class Company(name: String, address: Address)
case class Address(address1: String, address2: String, 
                   city: String, state: String, 
                   zip:String, country: String)

在我的Application.scala中，我定义了以下内容。

[1]. val companyForm = Form(of(Company.apply _, Company.unapply _)(
    "name" -> text,
    "address" -> mapping(
        "address1" -> nonEmptyText,
        "address2" -> text,
        "city" -> nonEmptyText,
        "state" -> nonEmptyText,
        "zip" -> nonEmptyText,
        "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )
)

[2]. val companyForm = Form(mapping(
    "name" -> text,
    "address" -> mapping(
        "address1" -> nonEmptyText,
        "address2" -> text,
        "city" -> nonEmptyText,
        "state" -> nonEmptyText,
        "zip" -> nonEmptyText,
        "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )(Company.apply, Company.unapply)
)

现在[1]适用于我，但当我尝试将其转换为[2]时，它会给我以下错误：

方法映射的参数太多：（apply：（String，models.Address）=＆gt; R）（unapply：R =＆gt; Option [（String，models.Address）]）play.api.data.Mapping [R]。

请告诉我我做错了什么。提前谢谢。

Answer 1

由于methode of()已弃用，您的表单必须如下所示：

     val companyForm = Form(
    mapping(
    "name" -> text,
    "address" -> mapping(
      "address1" -> nonEmptyText,
      "address2" -> text,
      "city" -> nonEmptyText,
      "state" -> nonEmptyText,
      "zip" -> nonEmptyText,
      "country" -> nonEmptyText
    )(Address.apply)(Address.unapply)
  )(Company.apply)(Company.unapply)
  )

所以您的问题出现在Company.Apply and Company.unapply方法

下面的语法中

方法映射的参数太多：（apply：（String，models.Address）=＆gt; R）（unapply：R =＆gt; Option [（String，models.Address）]）play.api.data.Mapping [R]

1 个答案: