Question

查询联系电话时出现以下sqlite异常：

05-05 04:25:47.276: E/AndroidRuntime(7369): android.database.sqlite.SQLiteException: near "s": syntax error: , while compiling:
 SELECT data1, data2 FROM view_data_restricted data WHERE (1 AND mimetype = 'vnd.android.cursor.item/phone_v2') AND ( DISPLAY_NAME = 'Seller's Permit Rose Agent')
05-05 04:25:47.276: E/AndroidRuntime(7369):     at android.database.DatabaseUtils.readExceptionFromParcel(DatabaseUtils.java:158)
05-05 04:25:47.276: E/AndroidRuntime(7369):     at android.database.DatabaseUtils.readExceptionFromParcel(DatabaseUtils.java:114)
05-05 04:25:47.276: E/AndroidRuntime(7369):     at android.content.ContentProviderProxy.bulkQueryInternal(ContentProviderNative.java:330)
05-05 04:25:47.276: E/AndroidRuntime(7369):     at android.content.ContentProviderProxy.query(ContentProviderNative.java:366)
05-05 04:25:47.276: E/AndroidRuntime(7369):     at android.content.ContentResolver.query(ContentResolver.java:245)

我对sqlite一无所知，因为我甚至没有直接使用它。我正在使用游标。异常的根是行：

phoneCursor = contentResolver.query(Phone.CONTENT_URI, new String[] { Phone.NUMBER, Phone.TYPE },
                " DISPLAY_NAME = '" + name + "'", null, null);

完整的方法是

public ArrayList<Contact> getContacts() {
    ArrayList<Contact> data = new ArrayList<Contact>();

    contactCursor = contentResolver.query(Contacts.CONTENT_URI, new String[] { Contacts.DISPLAY_NAME, BaseColumns._ID }, null, null, null);
    if (contactCursor != null) {
      String name = null;
      String phoneString = null;
      long phoneNumber = -1;
      long id;
      InputStream image = null;
      while (contactCursor.moveToNext()) {
        name = contactCursor.getString(contactCursor.getColumnIndex(Contacts.DISPLAY_NAME));
        image = Contacts.openContactPhotoInputStream(contentResolver, ContentUris.withAppendedId(Contacts.CONTENT_URI,
            contactCursor.getLong(contactCursor.getColumnIndex(BaseColumns._ID))));
        id = contactCursor.getLong(contactCursor.getColumnIndex(BaseColumns._ID));

        phoneCursor = contentResolver.query(Phone.CONTENT_URI, new String[] { Phone.NUMBER, Phone.TYPE },
            " DISPLAY_NAME = '" + name + "'", null, null);
        while (phoneCursor.moveToNext()) {
          ...
        }
      }
    }
    return data;
  }

Answer 1

android.database.sqlite.SQLiteException：near“s”：语法错误：，同时编译： SELECT data1，data2 FROM view_data_restricted data WHERE（1 AND mimetype ='vnd.android.cursor.item / phone_v2'）AND（DISPLAY_NAME ='卖方许可玫瑰代理'）

由于显示名称中的单引号而发生异常

试试这个

name=name.replace("'","''");

然后

 phoneCursor = contentResolver.query(Phone.CONTENT_URI, new String[] { Phone.NUMBER, Phone.TYPE },
            " DISPLAY_NAME = '" + name + "'", null, null);

Answer 2

由于name字符串中的单引号。一种方法是摆脱单引号，但这不是正确的方法。如果您希望代码在单引号和双引号中工作，请尝试使用rawQuery（）而不是使用.query（）方法。请参阅以上2个主题：Android quotes within an sql query string和handeling querying an item with a single quote in it。他们处理同样的问题。

Answer 3

理想情况下应该这样做，

phoneCursor = contentResolver.query(Phone.CONTENT_URI, new String[] { Phone.NUMBER, Phone.TYPE }, " DISPLAY_NAME = ?", new String[] {name}, null);

使用游标来获取联系人抛出sqlite异常

3 个答案: