Question

我是新手使用Access并尝试更改此查询：

SELECT 
   DateDiff("d", [Invoice]![TxnDate],[ReceivePaymentLine]![TxnDate]) AS ActualPaymentDays, 
   IIF ([ActualPaymentDays] < 90, 0.10, IIF ([ActualPaymentDays] < 120, 0.09, IID ([ActualPaymentDays] , 365, 0.05, 0))) AS PayPerValue
FROM 
   ReceivePaymentLine 
INNER JOIN 
   Invoice ON ReceivePaymentLine.AppliedToTxnTxnID = Invoice.TxnID

我制作“ActualPaymentDaysRate”表：

ActualPaymentDay1
PayPerValue1
ActualPaymentDay2
PayPerValue2
ActualPaymentDay3
PayPerValue3

我将上面的查询更改为此查询：

SELECT 
    DateDiff("d",[Invoice]![TxnDate],[ReceivePaymentLine]![TxnDate]) AS ActualPaymentDays, 
    IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay1],[ActualPaymentDaysRate.PayPerValue1], IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay2], [ActualPaymentDaysRate.PayPerValue2], IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay3],[ActualPaymentDaysRate.PayPerValue3], 0))) AS PayPerValue
FROM 
    ActualPaymentDaysRate, ReceivePaymentLine 
INNER JOIN 
    Invoice ON ReceivePaymentLine.AppliedToTxnTxnID = Invoice.TxnID

显示错误“不支持JOIN表达式”。

Answer 1

你不能混合使用旧样式和新样式连接语法。

添加另一个联接：

SELECT DateDiff("d",[Invoice]![TxnDate],[ReceivePaymentLine]![TxnDate]) AS ActualPaymentDays, IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay1],[ActualPaymentDaysRate.PayPerValue1],IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay2],[ActualPaymentDaysRate.PayPerValue2], IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay3],[ActualPaymentDaysRate.PayPerValue3], 0))) AS PayPerValue
FROM ReceivePaymentLine
INNER JOIN Invoice ON ReceivePaymentLine.AppliedToTxnTxnID = Invoice.TxnID
JOIN ActualPaymentDaysRate ON {some condition}

此外，您在查询中将JOIN拼写为“JON”。我纠正了这个。

Answer 2

你做错了是使用 ANSI SQL-89 语法和 ANSI SQL-92 JOIN语法

INNER JOIN的旧语法 ANSI SQL-89 ，您可以在其中指定由您在查询中使用逗号分隔的两个表名称，如下所示

SELECT <column list>
FROM ActualPaymentDaysRate, ReceivePaymentLine

ANSI SQL-92 语法，您使用JOIN关键字并使用您已完成的ON指定条件

 INNER JOIN Invoice ON ReceivePaymentLine.AppliedToTxnTxnID = Invoice.TxnID

但是你不能在同一个查询中同时使用它们。在您的查询中，您有三个表，因此使用三个INNER JOIN链接表。

如果忘记加入条件，不建议使用ANSI SQL-89语法，则不建议生成错误，而是在返回所有行的表之间应用笛卡尔积。

SELECT <column list>
FROM ActualPaymentDaysRate, ReceivePaymentLine 
--  WHERE <condition> excluded , NOT a INNER JOIN anymore but still no error

但如果您忘记了SQL-92语法中的条件，则会立即生成错误。

Answer 3

您的问题是您在内连接中指定了两个表名，需要两个内连接才能连接3个表。

看到这一点。

SELECT DateDiff("d",[Invoice]![TxnDate],[ReceivePaymentLine]![TxnDate]) AS ActualPaymentDays, 
IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay1],[ActualPaymentDaysRate.PayPerValue1],
IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay2],[ActualPaymentDaysRate.PayPerValue2], 
IIF ([ActualPaymentDays] < [ActualPaymentDaysRate.ActualPaymentDay3],[ActualPaymentDaysRate.PayPerValue3], 0))) AS PayPerValue
FROM ActualPaymentDaysRate INNER JOIN ReceivePaymentLine 
ON <Match Condition>
INNER JOIN Invoice 
ON ReceivePaymentLine.AppliedToTxnTxnID = Invoice.TxnID

SQL - 不支持连接表达式

3 个答案: