Question

我有四张桌子，公司，车辆，报价和电话请求。

公司可能会收到其车辆的报价和请求。

每个报价和请求都标有时间。

我想查找每个公司在每个月收到的报价和请求数，只要报价或请求数大于0。

我不知道如何分组这两个表中的月份相同。

这是我到目前为止所得到的：

SELECT
    company.name `company`,
    vehicle.name `vehicle`,
    DATE_FORMAT(COALESCE(quote.qtime, pr.date),'%Y-%m') `month`,
    COUNT(DISTINCT quote.qid) `quotes`,
    COUNT(DISTINCT pr.id) `phone_reqs`
FROM companies company
    LEFT JOIN vehicles vehicle ON vehicle.compid=company.cid
    LEFT JOIN quote_vehicle qv ON qv.vehicle_id=vehicle.vid
    LEFT JOIN quotes quote ON qv.quote_id=quote.qid
    LEFT JOIN phone_requests pr ON pr.vehicle_id=vehicle.vid AND quote.qtime IS NULL OR DATE_FORMAT(quote.qtime,'%Y-%m')=DATE_FORMAT(pr.date,'%Y-%m')
GROUP BY
    company.cid, `month`
HAVING
    quotes > 0 OR phone_reqs > 0
ORDER BY
    `month` DESC, `company` ASC

但它似乎将phone_reqs归因于错误的公司，可能是因为AND quote.qtime IS NULL OR DATE_FORMAT(quote.qtime,'%Y-%m')=DATE_FORMAT(pr.date,'%Y-%m')位。我不知道如何确保报价和请求在同一个月内发生。

Answer 1

可能这可以帮助

SELECT
    company.name `company`,
    vehicle.name `vehicle`,
    month,
    quote.quotes,
    pr.phone_reqs
FROM companies company
    LEFT JOIN vehicles vehicle ON vehicle.compid=company.cid
    LEFT JOIN quote_vehicle qv ON qv.vehicle_id=vehicle.vid
LEFT JOIN (SELECT COUNT(DISTINCT qid) quotes, DATE_FORMAT(qtime,'%Y-%m') `month` FROM quotes GROUP BY `month`) quote ON quote.qid = qv.quote_id
LEFT JOIN (SELECT COUNT(DISTINCT id) `phone_reqs`, DATE_FORMAT(date,'%Y-%m') `month` FROM phone_requests GROUP BY `month`) pr ON pr.phone_reqs = vehicle.vid AND quote.month = pr.month
GROUP BY  company.cid
HAVING
    quotes > 0 OR phone_reqs > 0
ORDER BY
    `month` DESC, `company` ASC

Answer 2

你说

...可能是因为AND quote.qtime IS NULL OR DATE_FORMAT(quote.qtime,'%Y-%m')=DATE_FORMAT(pr.date,'%Y-%m')位。

添加简单的WHERE子句怎么样？

SELECT
    company.name `company`,
    vehicle.name `vehicle`,
    DATE_FORMAT(COALESCE(quote.qtime, pr.date),'%Y-%m') `month`,
    COUNT(DISTINCT quote.qid) `quotes`,
    COUNT(DISTINCT pr.id) `phone_reqs`
FROM companies company
    LEFT JOIN vehicles vehicle ON vehicle.compid=company.cid
    LEFT JOIN quote_vehicle qv ON qv.vehicle_id=vehicle.vid
    LEFT JOIN quotes quote ON qv.quote_id=quote.qid
    LEFT JOIN phone_requests pr ON pr.vehicle_id=vehicle.vid
WHERE
  (quote.qtime IS NULL) OR (quote.qtime BETWEEN pr.date AND pr.date - 2592000)
GROUP BY
    company.cid, `month`
HAVING
    quotes > 0 OR phone_reqs > 0
ORDER BY
    `month` DESC, `company` ASC

注意：2592000代表30天（假设您的日期是时间戳）...

Answer 3

找出一些东西：

SELECT `month`, `company`, SUM(nquotes) nquotes, SUM(nphone) nphone  FROM ((
    SELECT
        DATE_FORMAT(quote.qtime,'%Y-%m') `month`,
        company.name `company`,
        COUNT(*) `nquotes`,
        0 `nphone`,
        company.cid `company_id`
    FROM
        companies company
        JOIN vehicles vehicle ON vehicle.compid=company.cid
        JOIN quote_vehicle qv ON qv.vehicle_id=vehicle.vid
        JOIN quotes quote ON qv.quote_id=quote.qid
    GROUP BY `month`, `company_id`
) UNION ALL (
    SELECT
        DATE_FORMAT(pr.date,'%Y-%m') `month`,
        company.name `company`,
        0 `nquotes`,
        COUNT(*) `nphone`,
        company.cid `company_id`
    FROM
        companies company
        JOIN vehicles vehicle ON vehicle.compid=company.cid
        JOIN phone_requests pr ON pr.vehicle_id=vehicle.vid
    GROUP BY `month`, `company_id`
)) master
GROUP BY `month`, `company_id`
ORDER BY `month` DESC, `company` ASC

如何根据时间从两个单独的表中获取计数？

3 个答案: