Question

我需要在UltraEdit脚本（JavaScript）中测试字符串$ A的长度，然后如果它小于x（例如：30）则用前导空格填充它。在Stack Overflow上有以下建议，但它似乎不适用于UltraEdit脚本。

$AAA .= (" " x (35 - length($AAA)));

建议表示赞赏。

PS：UltraEdit将JavaScript核心引擎用于脚本。

Answer 1

在UltraEdit脚本中使用的JavaScript核心中，没有函数可以打印格式化为字符串变量。

但是，使用前导空格或零创建对齐字符串非常容易。

数字的固定长度输出示例：

var nNumber = 30;            // number to output right aligned with 4 digits
var sAlignSpaces = "    ";   // string containing the spaces (or zeros) for aligning

// Convert integer number to decimal string.
var sNumber = nNumber.toString(10);
// Has the decimal string less than 4 characters as defined by sAlignSpaces?
if (sNumber.length < sAlignSpaces.length)
{
   // Build decimal string new with X spaces (here 2) from the alignment
   // spaces string and concatenate this string with the number string.
   sNumber = sAlignSpaces.substr(0,sAlignSpaces.length-sNumber.length) + sNumber;
}
// String sNumber has now always at least 4 characters with
// 0 to 3 leading spaces depending on decimal value of the number.

根据最高数字动态对齐正数的示例：

var nHighestNumber = 39428;  // highest number usually determined before
var nCurrentNumber = 23;     // current number to output right aligned

// Convert the highest number to a decimal string and get a copy
// of this string with every character replaced by character '0'.
// With highest number being 39428 the created string is "00000".
var sLeadingZeros = nHighestNumber.toString(10).replace(/./g,"0");

// Convert integer number to decimal string.
var sNumber = nCurrentNumber.toString(10);
// Has the decimal string of the current number less
// characters than the decimal string of the highest number?
if (sNumber.length < sLeadingZeros.length)
{
   // Build decimal string new with X (here 3) zeros from the alignment
   // string and concatenate this leading zero string with the number string.
   sNumber = sLeadingZeros.substr(0,sLeadingZeros.length-sNumber.length) + sNumber;
}
// String sNumber has now always at least 5 characters with 0 to 4
// leading zeros depending on decimal value of the positive number.

Answer 2

我认为你在寻找的是：

http://msdn.microsoft.com/en-us/library/66f6d830.aspx

如何填充带有前导空格的字符串？

2 个答案: