RGB888数据生成的Tiff图像不正确

Question

我正在尝试将RGB888图像数据转换为TIFF图像。但代码会生成不正确的图像。 我正在从文本文件中读取RGB数据。这是输出图像

黑色区域不应该在那里似乎代码使低RGB值为零。 我正在创建没有alpha通道的tiff图像。请帮助我理解这个问题。

TIFF *out= TIFFOpen("new.tif", "w");

int sampleperpixel = 3;
uint32 width=320;
uint32 height=240;
unsigned char image[width*height*sampleperpixel];
int pixval;
int count=0;


FILE *ptr=fopen("data.txt","r");
if (ptr!=NULL)
    {
      while(count<width*height)
        {fscanf(ptr,"%d",&pixval);            
        *(image+count)=(unsigned char)pixval;
        count++;}
    }
printf("%d\n",count);

TIFFSetField(out, TIFFTAG_IMAGEWIDTH, width);  // set the width of the image
TIFFSetField(out, TIFFTAG_IMAGELENGTH, height);    // set the height of the image
TIFFSetField(out, TIFFTAG_SAMPLESPERPIXEL, sampleperpixel);   // set number of channels per pixel
TIFFSetField(out, TIFFTAG_BITSPERSAMPLE, 8);    // set the size of the channels
TIFFSetField(out, TIFFTAG_ORIENTATION, ORIENTATION_TOPLEFT);    // set the origin of the image.
//   Some other essential fields to set that you do not have to understand for now.
TIFFSetField(out, TIFFTAG_PLANARCONFIG, PLANARCONFIG_CONTIG);
TIFFSetField(out, TIFFTAG_PHOTOMETRIC, PHOTOMETRIC_RGB);

tsize_t linebytes = sampleperpixel * width;
unsigned char *buf = NULL; 
//if (TIFFScanlineSize(out)<linebytes)
//  buf =(unsigned char *)_TIFFmalloc(linebytes);
//else
    buf = (unsigned char *)_TIFFmalloc(TIFFScanlineSize(out));




TIFFSetField(out, TIFFTAG_ROWSPERSTRIP, TIFFDefaultStripSize(out, width*sampleperpixel));

uint32 row ;
//Now writing image to the file one strip at a time
for (row = 0; row < height; row++)
{
    //memcpy(buf, &image[(height-row-1)*linebytes], linebytes);    // check the index here, and figure out why not using h*linebytes
    memcpy(buf, &image[(row)*linebytes], linebytes);        
if (TIFFWriteScanline(out, buf, row, 0) < 0)
    break;
}


TIFFClose(out);

if (buf)
 _TIFFfree(buf);

Answer 1

我在this tutorial找到了你的例子。由于您不是原作者，因此您应该始终发布一个链接来帮助他人并避免剽窃。

除了您添加的部分之外，该示例效果很好。要将文件读入字节数组，请使用它（在阅读fread之后）：

fread(image, 1, sizeof image, ptr);

在原始代码中，您省略了sampleperpixel

while(count<width*height*sampleperpixel) ...

因此您只能阅读图像的三分之一。