Question

我目前在页面上有一个从数据库中检索到的用户列表。与用户一起是关联的子对象，但我想要做的是在同一页面上而不是所有用户的列表，它只是一个当前登录到应用程序的用户。因此，他们无法查看所有用户详细信息，只能查看自己的特定详细信息和子对象。

DAO - 获取所有用户的方法

public List<Module> getSetterModules(Integer userId){

      Session session = sessionFactory.getCurrentSession();

      Query query = session.createQuery("FROM UserEntity as u WHERE 
              u.userId="+userId);

      UserEntity userEntity = (UserEntity) query.uniqueResult();

      return  new ArrayList<Module>(userEntity.getsModule());

用于检索用户列表和关联对象的dto，我只想通过其id检索一个用户（经过身份验证）并列出链接到它们的所有对象。我试图像这样实现它：

@RequestMapping(value = "/main", method = RequestMethod.GET)
 public String getRecords(@RequestParam("userId") Integer userId, ModelMap 

        model) {

    //Retrieve one user
     UserEntity user = userService.getUserByID(userId);
     UserEntityDTO userDTO = new UserEntityDTO();


     UserEntityDTO dto = new UserEntityDTO();
     dto.setUserId(user.getUserId());
     dto.setsModule(moduleService.getSetterModules(user.getUserId()));
     dto.setcModule(moduleService.getCheckerModules(user.getUserId()));

     userDTO.add(dto);
     }
     model.addAttribute("user", userDTO); 

      return "/main";}

我想了解如何从这里开始，或者是否有一种更简单的方式来吸引用户。

新DAO

@Transactional
public UserEntity getUserByID(Integer userId) {
    Session session = sessionFactory.getCurrentSession();

    UserEntity userEntity = (UserEntity) session.get(UserEntity.class, userId);
    userEntity.getsModule();

            return userEntity;}

控制器

   @RequestMapping(value = "/main/user/testing", method = RequestMethod.GET)
    public String getRecords(@RequestParam("userId") Integer userId, ModelMap 

        model) {
     UserEntity userEntity = userService.getUserByID(userId);

     model.addAttribute("user", userEntity);

     return "/main/user/testing";
 }

错误

     HTTP Status 400 - Required Integer parameter 'userId' is not present

编辑2：上面的实现url正在返回上面的错误，所以我尝试将id硬编码到url中：

   <c:url value="/main/user/testing/?userId=2" var="url"/><a href="<c:out 

   value='${url}'/>">test</a>

并将控制器更改为：

  @RequestMapping(value = "/main/user/testing{userId}", method = RequestMethod.GET)
    public String getRecords(@RequestParam("userId") Integer userId, ModelMap 

        model) {
     UserEntity userEntity = userService.getUserByID(userId);

     model.addAttribute("user", userEntity);

     return "/main/user/testing";
 }

但错误现在是：

    javax.servlet.jsp.JspTagException: Don't know how to iterate over supplied "items" in &lt;forEach&gt;
org.apache.taglibs.standard.tag.common.core.ForEachSupport.toForEachIterator(ForEachSupport.java:274)
org.apache.taglibs.standard.tag.common.core.ForEachSupport.supportedTypeForEachIterator(ForEachSupport.java:238)
org.apache.taglibs.standard.tag.common.core.ForEachSupport.prepare(ForEachSupport.java:155)
javax.servlet.jsp.jstl.core.LoopTagSupport.doStartTag(LoopTagSupport.java:256)
org.apache.jsp.WEB_002dINF.views.main.user.testing_jsp._jspx_meth_c_005fforEach_005f0(testing_jsp.java:181)
org.apache.jsp.WEB_002dINF.views.main.user.testing_jsp._jspService(testing_jsp.java:125)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.springframework.web.servlet.view.InternalResourceView.renderMergedOutputModel(InternalResourceView.java:238)
org.springframework.web.servlet.view.AbstractView.render(AbstractView.java:264)
org.springframework.web.servlet.DispatcherServlet.render(DispatcherServlet.java:1208)
org.springframework.web.servlet.DispatcherServlet.processDispatchResult(DispatcherServlet.java:992)
org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:939)
org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:856)
org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:915)
org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:811)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:796)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:330)
org.springframework.security.web.access.intercept.FilterSecurityInterceptor.invoke(FilterSecurityInterceptor.java:118)
org.springframework.security.web.access.intercept.FilterSecurityInterceptor.doFilter(FilterSecurityInterceptor.java:84)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.access.ExceptionTranslationFilter.doFilter(ExceptionTranslationFilter.java:113)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.session.SessionManagementFilter.doFilter(SessionManagementFilter.java:103)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.authentication.AnonymousAuthenticationFilter.doFilter(AnonymousAuthenticationFilter.java:113)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.servletapi.SecurityContextHolderAwareRequestFilter.doFilter(SecurityContextHolderAwareRequestFilter.java:54)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.savedrequest.RequestCacheAwareFilter.doFilter(RequestCacheAwareFilter.java:45)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.authentication.www.BasicAuthenticationFilter.doFilter(BasicAuthenticationFilter.java:150)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter.doFilter(AbstractAuthenticationProcessingFilter.java:183)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.authentication.logout.LogoutFilter.doFilter(LogoutFilter.java:105)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.context.SecurityContextPersistenceFilter.doFilter(SecurityContextPersistenceFilter.java:87)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.access.channel.ChannelProcessingFilter.doFilter(ChannelProcessingFilter.java:144)
org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:342)
org.springframework.security.web.FilterChainProxy.doFilterInternal(FilterChainProxy.java:192)
org.springframework.security.web.FilterChainProxy.doFilter(FilterChainProxy.java:160)
org.springframework.web.filter.DelegatingFilterProxy.invokeDelegate(DelegatingFilterProxy.java:346)
org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:259)

这是我想要的jsp：

   <table>
        <tr>
                    <th>User Id</th>
                    <th>Module Code</th>
                    <th>Module Name</th>
              </tr>


       <c:forEach items="${setter}" var="obj" >
        <c:forEach items="${obj.sModule}" var="module" >


            <tr>
                <td><c:out value="${obj.userId}" escapeXml="true" /></td>


                <td><c:out value="${module.moduleCode}" escapeXml="true" /></td>
                <td><c:out value="${module.moduleName}" escapeXml="true" /></td>



            </tr>
            </c:forEach>
        </c:forEach>
    </table>

我真的想知道如何获得用户和相关模块，而无需将userId硬编码到url中。任何帮助都会很棒。

Answer 1

在get（Documentation）

上查看Session方法

session.get(UserEntity.class, userId);

Spring通过id检索一个用户

1 个答案: