Question

当我执行搜索方法时，它给出了我运行时错误

error:- 05-04 14:04:00.227: E/AndroidRuntime(4559): Caused by: 
android.database.sqlite.SQLiteException: no such column: ww (code 1): , 
while compiling: SELECT DISTINCT faculty, deparment, name, officeNumber, 
phoneNumber, emailAddress, officeHour FROM teacherInfo WHERE name=ww

当用户输入姓名并显示有关此老师的所有信息时，我需要搜索教师姓名，例如姓名，教师，部门，电话，电子邮件，职业，办公时间

这是DBAdapter.java中的getRecord方法

public Cursor getRecord(String n1) throws SQLException 
{       
    Cursor mCursor =db.query(true,tableName , new String[] {facultyc,
                deparmentc, namec, officeNumberc,Phonec ,emailAddressc,officeHourc},namec + "=" + n1, null, null, null, null, null);


    if (mCursor != null) {
        mCursor.moveToFirst();
    }
    return mCursor;
}

和Information.java中的这个搜索方法

public void search(){
    db.open();
    Cursor c = db.getRecord(n);
    if (c.moveToFirst()){
        t1.setText(c.getString(0));
        t2.setText(c.getString(1));
        t3.setText(c.getString(2));
        t4.setText(c.getString(3));
        t5.setText(c.getString(4));
        t6.setText(c.getString(5));
        t7.setText(c.getString(6));

    }

    else
        Toast.makeText(this, "this Dr not found", Toast.LENGTH_LONG).show();
    db.close();
}

DBAdapter.java中的这个Oncreate方法

public void onCreate(SQLiteDatabase db) 
DATABASE_CREATE =
        "create table if not exists teacherInfo (teacherNumber INTEGER primary key autoincrement," 
        + "name TEXT not null, faculty TEXT,deparment TEXT,officeNumber INTEGER,officeHour TEXT, emailAddress TEXT,phoneNumber TEXT, location INTEGER );";
            {
                try {
                    db.execSQL(DATABASE_CREATE);    
                } catch (SQLException e) {
                    e.printStackTrace();
                }
            }

Answer 1

Cursor mCursor =db.query(true,tableName , new String[] {facultyc,
            deparmentc, namec, officeNumberc,Phonec ,emailAddressc,officeHourc},namec + "= ?", new String[] { n1 }, null, null, null, null);

字符串必须在引号中。

Answer 2

问题是你错过了字符串的引号！

最好像这样使用String参数：

public Cursor getRecord(String n1) throws SQLException 
{       
    Cursor mCursor =db.query(true,tableName , new String[] {facultyc,
                deparmentc,namec,officeNumberc,Phonec,emailAddressc,officeHourc},
                namec + "= ? ", 
                new String[] {ww}, null, null, null, null);


    if (mCursor != null) {
        mCursor.moveToFirst();
    }
    return mCursor;
}

通过这种方式，您可以避免任何错误，并且字符串特殊字符也会自动转义！

Answer 3

您的查询未经过清理。它应该是：

SELECT DISTINCT faculty, deparment, name, officeNumber, 
    phoneNumber, emailAddress, officeHour FROM teacherInfo WHERE name="ww"

Answer 4

您输入的查询错误。将其更改为 - ＆gt;

Cursor mCursor =db.query(true,tableName , new String[] {facultyc,
                deparmentc, namec, officeNumberc,Phonec ,emailAddressc,officeHourc},"name = " + n1, null, null, null, null, null);

android数据库中没有这样的列错误

4 个答案: