我有parentView
和subView childView
。
childView
位于parentView
的中间位置,大约只有它的一半。
我想在用户点按childView
时关闭parentView
。
如果UITapGestureRecognizer
打开,我的代码会在parentView
中创建childView
。
我的问题是当用户触摸任何视图时触发了点击事件,而不仅仅是parentView
。
因此,我想知道如果只触摸了parentView,我怎么才能让事件发生?如果触摸了父视图,我怎么能关闭子视图呢?
- (IBAction)selectRoutine:(id)sender {
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"Storyboard" bundle:nil];
createRoutinePopupViewController* popupController = [storyboard instantiateViewControllerWithIdentifier:@"createRoutinePopupView"];
popupController.view.center = CGPointMake(self.view.bounds.size.width / 2, self.view.bounds.size.height / 2);
_ass = popupController;
//Tell the operating system the CreateRoutine view controller
//is becoming a child:
[self addChildViewController:popupController];
//add the target frame to self's view:
[self.view addSubview:popupController.view];
//Tell the operating system the view controller has moved:
[popupController didMoveToParentViewController:self];
UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleSingleTap:)];
[singleTap setNumberOfTapsRequired:1];
[self.view addGestureRecognizer:singleTap];
}
-(void) handleSingleTap: (id) sender {
NSLog(@"TEST STRING");
}
答案 0 :(得分:2)
您需要使用UIGestureRecognizerDelegate,实现以下方法。
它将检查触摸的视图。
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
if( [touch view] != popupController.view)
return YES;
return NO;
}