JCombobox Listener如何在选择项目时启用它?

时间:2013-05-04 08:50:57

标签: java swing jdbc actionlistener jcombobox

我有一个显示名称来自数据库Patients_Details的JComboBox

public void ComboItem() {

chooser.removeAllItems();
chooser.addItem("Please Select...");
try {   
         String sql="select * from Patients_Details";
         pst = conn.prepareStatement(sql);
         rs=pst.executeQuery();
        while (rs.next()) {
            String id = rs.getString("Patient_ID"); // Get the Id
            String name = rs.getString("Name"); // Get the Name 

            ComboItem comboItem = new ComboItem(id, name); // Create a new ComboItem
            chooser.addItem(comboItem); // Put it into the ComboBox
            String tmp=comboItem.getid();
        }
    } catch (SQLException sqle) {
        System.out.println(sqle);
    }
}

这是来自comboitem类,它只返回名称而不是id

  public String toString() {
    return this.name  ;
   }

我的问题是如何获取选择项以便可以执行此操作我不知道如何执行此操作我已经尝试了大约2个小时的所有代码 任何帮助将不胜感激

NB我是Java初学者

  private void chooserPopupMenuWillBecomeInvisible(javax.swing.event.PopupMenuEvent evt) {

    try{
      String sql="select * from Patients_Details where Patient_ID=? ";
      pst=conn.prepareStatement(sql);
      rs=pst.executeQuery();
      if(rs.next()){
      String add1=rs.getString("Patient_ID");
      txtpatientid.setText(add1);
      String add2=rs.getString("Name");
      txtname.setText(add2);
      String add3=rs.getString("Age");
      txtage.setText(add3);
      String add4=rs.getString("Gender");
      txtgender.setText(add4);
      String add5=rs.getString("Date");
      txtdate.setText(add5);
       }
  }
  catch(Exception e) {
    JOptionPane.showMessageDialog(null,e ); 
  }
}  

1 个答案:

答案 0 :(得分:2)

只需在组合框中添加ActionListener即可。调用actionPerformed时,您可以查找所选值并调用所需的方法。

例如:

chooser.addActionListener(new ActionListener() {
    public void actionPerformed(ActionEvent evt) {
        Object selectedValue = chooser.getSelectedValue();
        // carry on with what ever you need
    }
});

看看......

了解更多详情