Question

我目前一直坚持使用C ++问题大约一个半小时。这是问题：

编写一个程序，生成0到9之间的100个随机整数，并显示每个数字的计数。（提示：使用rand（）％10生成0到9之间的随机整数。使用十个整数的数组，说计数，存储O的数量，l ,. ..，9's。）

这就是我到目前为止所拥有的。我认为我非常接近，但我对每个随机整数的出现次数（或计数）保持“0”。任何帮助将不胜感激。

const int SIZE = 100;

int main()
{
int integers[SIZE];
int index;
int zero = 0;
int one = 0;
int two = 0;
int three = 0;
int four = 0;
int five = 0;
int six = 0;
int seven = 0;
int eight = 0;
int nine = 0;

cout << "The following 100 integers are random:" << endl;
cout << endl;

srand(time(0));

for (index = 0; index < SIZE; index++)
{
    integers[SIZE] = rand() % 10;
    cout << integers[SIZE] << " ";
}

cout << endl;

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 0)
    {
        zero += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 1)
    {
        one += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 2)
    {
        two += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 3)
    {
        three += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 4)
    {
        four += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 5)
    {
        five += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 6)
    {
        six += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 7)
    {
        seven += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 8)
    {
        eight += 1;
    }
}

for (index = 0; index < SIZE; index++)
{
    if (integers[index] == 9)
    {
        nine += 1;
    }
}

cout << "The number of zeros in the random list are " << zero << endl;
cout << "The number of ones in the random list are " << one << endl;
cout << "The number of twos in the random list are " << two << endl;
cout << "The number of threes in the random list are " << three << endl;
cout << "The number of fours in the random list are " << four << endl;
cout << "The number of fives in the random list are " << five << endl;
cout << "The number of sixes in the random list are " << six << endl;
cout << "The number of sevens in the random list are " << seven << endl;
cout << "The number of eights in the random list are " << eight << endl;
cout << "The number of nines in the random list are " << nine << endl;

getch();

return 0;

}

Answer 1

您有未定义的行为，因为您使用SIZE作为数组的索引而不是index：

for (index = 0; index < SIZE; index++)
{
    integers[SIZE] = rand() % 10;
    cout << integers[SIZE] << " ";
}

这将访问数组的边界之外（因为范围是从0到SIZE-1）。在循环体内，将SIZE更改为index。

但是，我认为它会帮助您重新阅读您的问题陈述。具体做法是：

使用十个整数的数组，比如counts来存储0，1，...，9s的计数

您使用数组来存储随机数。这根本不是必需的。您无需跟踪生成的数字。你只需要在适当的数量上加1，然后你就可以简单地丢弃随机数。

你应该只有一个名为counts的数组，其中counts[0]存储到目前为止0的数量，counts[1]存储1的数量然后你不需要这些可怕的变量叫zero，one，two，等等。如果您发现自己定义了类似的变量名称（其中包含的数字越来越多），那么您应该使用数组代替。

随机整数/出现（C ++）问题

1 个答案: