Question

我有传入的JSON字符串，我需要解组到JAXB带注释的对象。我正在使用jettison这样做。 JSON字符串如下所示：

{ 
  objectA : 
  { 
    "propertyOne" : "some val", 
    "propertyTwo" : "some other val",
    objectB : 
    {
      "propertyA" : "some val",
      "propertyB" : "true" 
    }
  }
}

ObjectA代码如下所示：

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "objectA")
public class ObjectA {
    @XmlElement(required = true)
    protected String propertyOne;
    @XmlElement(required = true)
    protected String propertyTwo;
    @XmlElement(required = true)
    protected ObjectB objectB;
}

ObjectB类代码如下所示：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "objectB")
public class ObjectB {
    @XmlElement(required = true)
    protected String propertyA;
    @XmlElement(required = true)
    protected boolean propertyB;
}

用于解组的代码：

JAXBContext jc = JAXBContext.newInstance(OnjectA.class);
JSONObject obj = new JSONObject(theJsonString);
Configuration config = new Configuration();

MappedNamespaceConvention con = new MappedNamespaceConvention(config);
XMLStreamReader xmlStreamReader = new MappedXMLStreamReader(obj,con);
Unmarshaller unmarshaller = jc.createUnmarshaller();

ObjectA obj = (ObjectA) unmarshaller.unmarshal(xmlStreamReader);

它不会抛出任何异常或警告。会发生什么是ObjectB被实例化，但它的属性都没有设置它们的值，即propertyA为null，propertyB的默认值为false。我一直在努力弄清楚为什么这不起作用。有人可以帮忙吗？

Answer 1

注意：我是EclipseLink JAXB (MOXy)主管，是JAXB (JSR-222)专家组的成员。

模型上的JAXB映射似乎是正确的。下面是示例代码，其中我使用您在问题中给出的确切模型以及通过EclipseLink MOXy提供的JSON绑定：

<强>演示

package forum16365788;

import java.io.File;
import java.util.*;
import javax.xml.bind.*;
import org.eclipse.persistence.jaxb.JAXBContextProperties;

public class Demo {

    public static void main(String[] args) throws Exception {
        Map<String, Object> properties = new HashMap<String, Object>(1);
        properties.put(JAXBContextProperties.MEDIA_TYPE, "application/json");
        JAXBContext jc = JAXBContext.newInstance(new Class[] {ObjectA.class}, properties);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File json = new File("src/forum16365788/input.json");
        ObjectA objectA = (ObjectA) unmarshaller.unmarshal(json);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(objectA, System.out);
    }

}

<强> input.json /输出

以下是我使用的JSON。应引用密钥objectA和objectB，您的问题中没有这个。

{
   "objectA" : {
      "propertyOne" : "some val",
      "propertyTwo" : "some other val",
      "objectB" : {
         "propertyA" : "some val",
         "propertyB" : true
      }
   }
}

了解更多信息

从json解组嵌套对象

1 个答案: