Question

我有一个如下所示的XML：

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<Items>
  <Category Name="Alfa">
    <Item Name="A1" Signature="3136323700000000"/>
    <Item Name="A2" Signature="3136333400000000"/>
    <Item Name="A3" Signature="3136323800000000"/>
    <Item Name="A4" Signature="3136333300000000"/>
    ... More Items
  </Category>
  <Category Name="Beta">
    <Item Name="B1" Signature="3136323700000000"/>
    <Item Name="B2" Signature="3136333400000000"/>
    <Item Name="B3" Signature="3136323800000000"/>
    <Item Name="B4" Signature="3136333300000000"/>
    ... More Items
  </Category>
  ... More Categories
</Items>

我想用它反序列化的类看起来像这样：

public sealed class Item
{
    private String m_Category;
    private String m_Name;
    private String m_Signature;

    public String Category
    {
        get { return m_Category; }
    }

    public String Name
    {
        get { return m_Name; }
    }

    public String Signature
    {
        get { return m_Signature; }
    }

    public Item(String category, String name, String signature)
    {
        m_Category = category;
        m_Name = name;
        m_Signature = signature;
    }
}

如何反序列化它以便从父元素的Name属性中获取Category属性？如果不可能，我可以使用哪种替代方法？

Answer 1

如何使用Linq To Xml？

var items = XDocument.Parse(xml)
                .Descendants("Item")
                .Select(c => new Item(c.Parent.Attribute("Name").Value, 
                                      c.Attribute("Name").Value, 
                                      c.Attribute("Signature").Value))
                .ToList();

使用父属性进行XML反序列化

1 个答案: