Question

我想使用我的django模型生成一个列表

说我有这些模特：

class AlarmServer(models.Model):
    ip = models.IPAddressField()

和这样的清单

server_ips = [i.ipfor i in AlarmServer.objects.all()]

似乎不起作用，我做错了什么？

Answer 1

server_ips = [i.ip for i in AlarmServer.objects.all()]

应该工作（我只是添加了一个空格）。我试过这个如下

mez@stupor % ./manage.py shell
Python 2.5.2 (r252:60911, Oct  5 2008, 19:24:49) 
[GCC 4.3.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
(InteractiveConsole)
>>> from mysite_org.videos.models import Video
>>> url_list = [v.url for v in Video.objects.all()]
>>> url_list
[u'http://media.mysite.org/videos/sblug_jan2009.flv', u'http://media.mysite.org/videos/sblug_feb2009.flv', u'http://media.mysite.org/videos/phpwm_mar2009.flv', u'http://media.mysite.org/videos/sblug_may2009.flv', u'http://media.mysite.org/videos/sblug_june2009.flv', u'http://media.mysite.org/videos/sblug_sep2009.flv', u'http://media.mysite.org/videos/bugjam-oct-2009.flv']

Answer 2

values_list

server_ips = [i[0] for i in AlarmServer.objects.values_list('ip')]

django模型对象到python列表

2 个答案: