我在从我的对象列表中填充树视图时出现问题。我一直在谷歌上寻找解决方案，我发现一些话题与我的问题很接近，但没有人解决它。
我有一个列表，其中包含每个对象的属性：名称和组。
我想填写我的树视图，如下所示：
+---Group 1
| |
| +--------object.Name <--
| +--------object.Name <-- all objects with object.Group = Group 1
| +--------object.Name <--
|
+---Group 2
| |
| +--------object.Name <--
| +--------object.Name <-- all objects with object.Group = Group 2
| +--------object.Name <--
|
等等。
感谢。
答案 0 :(得分：3)
工作得非常好，谢谢。我刚刚在else的开头和末尾加了几行。
private void PopulateTreeView()
{
ListOfObjectsSorted = ListOfObjects.OrderBy(r => r.Group).ToList();
var topNode = new TreeNode("Select all");
treeView1.Nodes.Add(topNode);
string currentGroup = ListOfObjectsSorted.First().Group;
var treeNodes = new List<TreeNode>();
var childNodes = new List<TreeNode>();
foreach (Object obj in ListOfObjectsSorted )
{
if (currentGroup == rule.Group)
childNodes.Add(new TreeNode(obj.Name));
else
{
if (childNodes.Count > 0)
{
treeNodes.Add(new TreeNode(currentGroup, childNodes.ToArray()));
childNodes = new List<TreeNode>();
}
childNodes.Add(new TreeNode(obj.Name));
currentGroup = obj.Group;
}
}
if (childNodes.Count > 0)
{
treeNodes.Add(new TreeNode(currentGroup, childNodes.ToArray()));
}
treeView1.Nodes[0].Nodes.AddRange(treeNodes.ToArray());
}
答案 1 :(得分：2)
您的问题是技术问题还是如何处理？您可以按object.Group排序，然后在每次更改组时创建顶级节点。
编辑： 下面是一些示例代码，我没有对其进行测试，因此将其作为指导原则进行处理：
string currentGroup = null;
List<TreeNode> treeNodes = new List<TreeNode>();
List<TreeNode> childNodes = new List<TreeNode>();
foreach (BusinessObject obj in objectList)
{
if (currentGroup == obj.Group)
childNodes.Add(new TreeNode(obj.Name));
else
{
if (childNodes.Count > 0)
{
treeNodes.Add(new TreeNode(currentGroup, childNodes.ToArray()));
childNodes = new List<TreeNode>();
}
currentGroup = obj.Group;
}
}
if (childNodes.Count > 0)
{
treeNodes.Add(new TreeNode(currentGroup, childNodes.ToArray()));
}
treeView.Nodes.AddRange(treeNodes.ToArray());
答案 2 :(得分：1)
这里有一些在VB ......
尝试
Me.Cursor = Cursors.WaitCursor
If rtb.Visible Then line = rtb.Lines
Dim i, j As Integer
Dim myLst As New ListBox
Dim nod0 As New TreeNode
Dim nod1 As New TreeNode
Dim nodGet As New TreeNode
Dim nodSet As New TreeNode
'Aktualna pozicia
If trw.SelectedNode Is Nothing Then
Else
nodGet = trw.SelectedNode
End If
For Each nod0 In trw.Nodes
If nod0.IsExpanded Then
myLst.Items.Add(nod0.Tag)
For Each nod1 In nod0.Nodes
If nod1.IsExpanded Then myLst.Items.Add(nod1.Tag)
Next
End If
Next
Dim cntr() As Integer = {-1, -1, -1}
trw.Nodes.Clear()
trw.ShowPlusMinus = False
trw.ShowRootLines = False
trw.CheckBoxes = False
For i = 0 To UBound(line)
If Mid(line(i), 1, 1) = "\" Then
j = line(i).IndexOf(dod)
If j > 0 Then
s = Mid(line(i), 1, j)
Else
s = line(i)
End If
If Mid(s, 1, 4) = "\\\\" Then
trw.Nodes.Add(Mid(s, 5))
cntr(0) = cntr(0) + 1
cntr(1) = -1
cntr(2) = -1
trw.Nodes(cntr(0)).Tag = s
trw.Nodes(cntr(0)).ImageIndex = 4
trw.Nodes(cntr(0)).SelectedImageIndex = 5
If trw.Nodes(cntr(0)).Tag = nodGet.Tag Then nodSet = trw.Nodes(cntr(0))
Else
If Mid(s, 1, 3) = "\\\" Then
If cntr(0) = -1 Then trw.Nodes.Add("...") : cntr(0) = 0 : cntr(1) = -1
trw.Nodes(cntr(0)).Nodes.Add(Mid(s, 4))
cntr(1) = cntr(1) + 1
cntr(2) = -1
trw.Nodes(cntr(0)).Nodes(cntr(1)).Tag = trw.Nodes(cntr(0)).Tag.ToString & eol & s
trw.Nodes(cntr(0)).Nodes(cntr(1)).ImageIndex = 1
trw.Nodes(cntr(0)).Nodes(cntr(1)).SelectedImageIndex = 2
If trw.Nodes(cntr(0)).Nodes(cntr(1)).Tag = nodGet.Tag Then nodSet = trw.Nodes(cntr(0)).Nodes(cntr(1))
Else
If Mid(s, 1, 2) = "\\" Then
If cntr(0) = -1 Then trw.Nodes.Add("...") : cntr(0) = 0 : cntr(1) = -1
If cntr(1) = -1 Then trw.Nodes(cntr(0)).Nodes.Add("...") : cntr(1) = 0 : cntr(2) = -1
trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes.Add(Mid(s, 3))
cntr(2) = cntr(2) + 1
trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes(cntr(2)).Tag = trw.Nodes(cntr(0)).Nodes(cntr(1)).Tag.ToString & eol & s
trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes(cntr(2)).ImageIndex = 3
trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes(cntr(2)).SelectedImageIndex = 4
If trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes(cntr(2)).Tag = nodSet.Tag Then nodSet = trw.Nodes(cntr(0)).Nodes(cntr(1)).Nodes(cntr(2))
End If
End If
End If
End If
Next i
'Navrat na aktualnu poziciu
Application.DoEvents()
For i = 0 To myLst.Items.Count - 1
For Each nod0 In trw.Nodes
If nod0.Tag = myLst.Items(i).ToString Then nod0.Expand()
For Each nod1 In nod0.Nodes
If nod1.Tag = myLst.Items(i).ToString Then nod1.Expand()
Next
Next
Next i
Application.DoEvents()
If nodSet.Tag <> "" Then trw.SelectedNode = nodSet
Catch ex As Exception
MsgBox(ex.ToString, MsgBoxStyle.Exclamation)
Finally
Me.Cursor = Cursors.Default
End Try
答案 3 :(得分：0)
5年后。...
调用>> PrintProperties（null，yourObject，0）;
public void PrintProperties(TreeNode parentNode, object obj, int indent)
{
if (obj == null) return;
string indentString = new string(' ', indent);
Type objType = obj.GetType();
PropertyInfo[] properties = objType.GetProperties();
foreach (PropertyInfo property in properties)
{
object propValue = new object();
if (property.CanRead)
propValue = property.GetValue(obj, null);
if (IsSimpleType(property.PropertyType))
{
//Console.WriteLine("{0}{1}:", indentString, property.Name);
if (parentNode != null)
{
parentNode.Nodes.Add(property.Name, property.Name +": " + (propValue != null ? propValue.ToString() : string.Empty));
}
else
{
treeView.Nodes.Add(property.Name, property.Name + ": " + (propValue != null ? propValue.ToString() : string.Empty));
}
}
else if (typeof(IEnumerable).IsAssignableFrom(property.PropertyType))
{
TreeNode node;
if (parentNode != null)
{
node = parentNode.Nodes.Add(property.Name, property.Name);
}
else
{
node = treeView.Nodes.Add(property.Name, property.Name);
}
//Console.WriteLine("{0}{1}:", indentString, property.Name);
IEnumerable enumerable = (IEnumerable)propValue;
foreach (object child in enumerable)
PrintProperties(node, child, indent + 2);
}
else
{
TreeNode node;
if (parentNode != null)
{
node = parentNode.Nodes.Add(property.Name, property.Name);
}
else
{
node = treeView.Nodes.Add(property.Name, property.Name);
}
PrintProperties(node, propValue, indent + 2);
}
}
}
public static bool IsSimpleType(Type type)
{
return
type.IsValueType ||
type.IsPrimitive ||
new Type[]
{
typeof(String),
typeof(Decimal),
typeof(DateTime),
typeof(DateTimeOffset),
typeof(TimeSpan),
typeof(Guid)
}.Contains(type) ||
Convert.GetTypeCode(type) != TypeCode.Object;
}
答案 4 :(得分：0)
这里是一个基于@PrepucioArgentino的答案的版本，它对集合中的复杂类型以及结构要好一些。 您还可以根据属性名称忽略属性（在整个结构中）。但通常您希望在此处传递一个空列表。
public static class TreeNodeHelper
{
public static void PrintProperties(TreeNode parentNode, object obj, int indent, TreeView treeView, ICollection<string> ignoredPropertyNames)
{
string indentString = new string(' ', indent); // used for debugging
if (obj == null)
return;
var objType = obj.GetType();
var properties = objType.GetProperties()
.Where(x => !ignoredPropertyNames.Contains(x.Name))
.ToList();
foreach (var property in properties)
{
if (property.Name.ToUpper().Contains("DiagMessage".ToUpper()))
{
// TODO rem test code
}
var propValue = new object();
if (property.CanRead)
propValue = property.GetValue(obj, null);
if (IsSimpleType(property.PropertyType))
{
Debug.WriteLine("{0}{1}:", indentString, property.Name);
if (parentNode != null)
{
parentNode.Nodes.Add(property.Name,
$"{property.Name}: {(propValue != null ? propValue.ToString() : string.Empty)}");
}
else
{
treeView.Nodes.Add(property.Name,
$"{property.Name}: {(propValue != null ? propValue.ToString() : string.Empty)}");
}
}
else if (typeof(IEnumerable).IsAssignableFrom(property.PropertyType))
{
TreeNode collectionRootNode;
if (parentNode != null)
{
collectionRootNode = parentNode.Nodes.Add(property.Name, property.Name);
}
else
{
collectionRootNode = treeView.Nodes.Add(property.Name, property.Name);
}
Debug.WriteLine("{0}{1}:", indentString, property.Name);
var enumerable = (IEnumerable)propValue;
var count = 0;
foreach (var child in enumerable)
{
count++;
if (!IsSimpleType(child.GetType()))
{
var entryRootNode = collectionRootNode.Nodes.Add($"{property.Name}[{count}]",
$"{property.Name}[{count}]");
PrintProperties(entryRootNode, child, indent + 2, treeView, ignoredPropertyNames);
}
else
{
collectionRootNode.Nodes.Add($"{property.Name}[{count}]", $"{property.Name}[{count}]: {child}");
}
}
}
else
{
TreeNode node;
if (parentNode != null)
{
node = parentNode.Nodes.Add(property.Name, property.Name);
}
else
{
node = treeView.Nodes.Add(property.Name, property.Name);
}
PrintProperties(node, propValue, indent + 2, treeView, ignoredPropertyNames);
}
}
}
public static bool IsSimpleType(Type type)
{
if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
{
// nullable type, check if the nested type is simple.
return IsSimpleType(type.GetGenericArguments()[0]);
}
return type.IsPrimitive
|| ((IList)new[]
{
// Structs that are 'simple types', expand on this when needed.
typeof(DateTime),
typeof(DateTimeOffset),
typeof(TimeSpan),
typeof(Guid)
}).Contains(type)
|| type.IsEnum
|| type == typeof(string)
|| type == typeof(decimal);
}
}
TreeNodeHelper.PrintProperties(null, firstMotor, 0, treeView1, new List<string>(new[]{ "Creator", "PlcTag", "PlcComponentCreationInfo" }));