Question

我有一个由6个字母组成的字符串，例如：＆＃34; abcdef＆＃34;。我需要添加＆＃34;。＆＃34;每两个字符就这样：＆＃34; ab.cd.ef＆＃34;。我在java工作，我试过这个：

private String FormatAddress(String sourceAddress) {
    char[] sourceAddressFormatted = new char[8];
    sourceAddress.getChars(0, 1, sourceAddressFormatted, 0);
    sourceAddress += ".";
    sourceAddress.getChars(2, 3, sourceAddressFormatted, 3);
    sourceAddress += ".";
    sourceAddress.getChars(4, 5, sourceAddressFormatted, 6);
    String s = new String(sourceAddressFormatted);
    return s;
}

但是我收到了一些奇怪的值，例如[C @ 2723b6。

提前致谢：）

Answer 1

试试regexp：

输入：

abcdef

<强>代码：

System.out.println("abcdef".replaceAll(".{2}(?!$)", "$0."));

输出

ab.cd.ef

Answer 2

您应该将其修复为

    String sourceAddress = "abcdef";
    String s = sourceAddress.substring(0, 2);
    s += ".";
    s += sourceAddress.substring(2, 4);
    s += ".";
    s += sourceAddress.substring(4, 6);
    System.out.println(s);

你也可以用正则表达式做同样的事情，这是一个单线解决方案

    String s = sourceAddress.replaceAll("(\\w\\w)(?=\\w\\w)", "$1.");
    System.out.println(s);

Answer 3

试试这个：

String result="";
String str ="abcdef";
for(int i =2; i<str.length(); i=i+2){
     result = result + str.substring(i-2 , i) + ".";
}
result = result + str.substring(str.length()-2);

Answer 4

private String formatAddress(String sourceAddress) {
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < sourceAddress.length(); i+=2) {
        sb.append(sourceAddress.substring(i, i+2));
        if (i != sourceAddress.length()-1) {
            sb.append('.');
        }
    }
    return sb.toString();
}

如何在特定索引中的字符串中添加字符？

4 个答案: