Question

我正在尝试使用我从当前位置检索到的location_id作为Facebook事件创建的参数，这是我的代码：

我已经设置了所有授权令牌和扩展权限，它确实返回了有效的位置ID;但是，在我将location_id插入事件创建参数数组后，它没有创建事件。（所有其他字段都是通过表格设置的。）有人可以帮忙吗？

这是我的代码：

  try{
    //default location
    $event_url =  $my_url . 'create_group.php';
    $event_location = $facebook->api('/me?fields=location');
    $event_location_id = $event_location['id'];
    echo $event_location_id;
   }

   catch(Exception $e)
   {
   echo $e;
   }



$params= array(

    "name" => "[Study Group]".$_POST['name'],
    "description" => $_POST['description'],
    "location_id" => $event_location_id,
    "start_time" => $_POST['start_time'].$_POST['time_zone'],
    "privacy_type" => $_POST['privacy_type'],
    "end_time" => $_POST['end_time'].$_POST['time_zone']
);

以下是我的例外情况：

Exception: The place or event you attempted to plan to attend is invalid. Please try a different place or event.

异常通过以下方式解决：改变：

$event_location_id = $event_location['id'];

到

$event_location_id= $event_location['location']['id'];

Answer 1

异常告诉自己错误是Location Id的错误值。正如你自己调试的那样，这是因为你将其检索为

$event_location_id = $event_location['id'];

应该将其检索为

$event_location_id= $event_location['location']['id'];

用于Facebook事件创建的location_id

1 个答案: