表格:
auth(auth, age), book(title,auth,pubname), publ(pubname,address)
我试图提出一个查询,打印出版商的地址,这里只发表了一本书,这是我的尝试,请纠正我,如果我错了:这不是作业,它是研究的一部分即将进行的测试指南。
SELECT address
FROM publ
WHERE pubname
IN ( SELECT pubname
FROM book
GROUP BY pubname
HAVING count(*) = 1)
我认为这是对的,但不确定。
答案 0 :(得分:0)
按查询分组的内部联接将解决您的问题。
select address from from publ pb
inner join
(SELECT pubname
FROM book
GROUP BY pubname
HAVING count(*) = 1) b
on b.pubname = pb.pubname