我有这个代码。它应该检查文件是否存在,如果存在则打开它。如果文件存在,它确实有效,但如果文件不存在,那么每当我将文本框留空并单击提交按钮时,它就会失败。我想要的是,如果文本框为空,则显示错误消息,就像文件不存在一样。
运行时错误“1004”
Dim File As String
File = TextBox1.Value
Dim DirFile As String
DirFile = "C:\Documents and Settings\Administrator\Desktop\" & File
If Dir(DirFile) = "" Then
MsgBox "File does not exist"
Else
Workbooks.Open Filename:=DirFile
End If
答案 0 :(得分:51)
类似这样的事情
最好使用工作簿变量来提供已打开工作簿的进一步控制(如果需要)
更新以测试该文件名是一个实际工作簿 - 这也使初始检查变得多余,而不是向用户发送消息而不是文本框为空
Dim strFile As String
Dim WB As Workbook
strFile = Trim(TextBox1.Value)
Dim DirFile As String
If Len(strFile) = 0 Then Exit Sub
DirFile = "C:\Documents and Settings\Administrator\Desktop\" & strFile
If Len(Dir(DirFile)) = 0 Then
MsgBox "File does not exist"
Else
On Error Resume Next
Set WB = Workbooks.Open(DirFile)
On Error GoTo 0
If WB Is Nothing Then MsgBox DirFile & " is invalid", vbCritical
End If
答案 1 :(得分:31)
我使用此函数检查文件是否存在:
Function IsFile(ByVal fName As String) As Boolean
'Returns TRUE if the provided name points to an existing file.
'Returns FALSE if not existing, or if it's a folder
On Error Resume Next
IsFile = ((GetAttr(fName) And vbDirectory) <> vbDirectory)
End Function
答案 2 :(得分:22)
为了检查存在,还可以使用(适用于文件和文件夹):
Not Dir(DirFile, vbDirectory) = vbNullString
如果文件或目录存在,结果为True
。
示例:
If Not Dir("C:\Temp\test.xlsx", vbDirectory) = vbNullString Then MsgBox "exists" Else MsgBox "does not exist" End If
答案 3 :(得分:2)
简洁明了的方法:
Public Function IsFile(s)
IsFile = CreateObject("Scripting.FileSystemObject").FileExists(s)
End Function
答案 4 :(得分:0)
可能是由文件名变量
引起的File = TextBox1.Value
应该是
Filename = TextBox1.Value
答案 5 :(得分:0)
我把它扔出去然后躲开。 检查文件是否存在的通常原因是在尝试打开文件时避免错误。如何使用错误处理程序来处理:
Function openFileTest(filePathName As String, ByRef wkBook As Workbook, _
errorHandlingMethod As Long) As Boolean
'Returns True if filePathName is successfully opened,
' False otherwise.
Dim errorNum As Long
'***************************************************************************
' Open the file or determine that it doesn't exist.
On Error Resume Next:
Set wkBook = Workbooks.Open(fileName:=filePathName)
If Err.Number <> 0 Then
errorNum = Err.Number
'Error while attempting to open the file. Maybe it doesn't exist?
If Err.Number = 1004 Then
'***************************************************************************
'File doesn't exist.
'Better clear the error and point to the error handler before moving on.
Err.Clear
On Error GoTo OPENFILETEST_FAIL:
'[Clever code here to cope with non-existant file]
'...
'If the problem could not be resolved, invoke the error handler.
Err.Raise errorNum
Else
'No idea what the error is, but it's not due to a non-existant file
'Invoke the error handler.
Err.Clear
On Error GoTo OPENFILETEST_FAIL:
Err.Raise errorNum
End If
End If
'Either the file was successfully opened or the problem was resolved.
openFileTest = True
Exit Function
OPENFILETEST_FAIL:
errorNum = Err.Number
'Presumabley the problem is not a non-existant file, so it's
'some other error. Not sure what this would be, so...
If errorHandlingMethod < 2 Then
'The easy out is to clear the error, reset to the default error handler,
'and raise the error number again.
'This will immediately cause the code to terminate with VBA's standard
'run time error Message box:
errorNum = Err.Number
Err.Clear
On Error GoTo 0
Err.Raise errorNum
Exit Function
ElseIf errorHandlingMethod = 2 Then
'Easier debugging, generate a more informative message box, then terminate:
MsgBox "" _
& "Error while opening workbook." _
& "PathName: " & filePathName & vbCrLf _
& "Error " & errorNum & ": " & Err.Description & vbCrLf _
, vbExclamation _
, "Failure in function OpenFile(), IO Module"
End
Else
'The calling function is ok with a false result. That is the point
'of returning a boolean, after all.
openFileTest = False
Exit Function
End If
End Function 'openFileTest()
答案 6 :(得分:0)
这是我更新的代码。在保存之前检查版本是否存在,并将其另存为下一个可用版本号。
Sub SaveNewVersion()
Dim fileName As String, index As Long, ext As String
arr = Split(ActiveWorkbook.Name, ".")
ext = arr(UBound(arr))
fileName = ActiveWorkbook.FullName
If InStr(ActiveWorkbook.Name, "_v") = 0 Then
fileName = ActiveWorkbook.Path & "\" & Left(ActiveWorkbook.Name, InStr(ActiveWorkbook.Name, ".") - 1) & "_v1." & ext
End If
Do Until Len(Dir(fileName)) = 0
index = CInt(Split(Right(fileName, Len(fileName) - InStr(fileName, "_v") - 1), ".")(0))
index = index + 1
fileName = Left(fileName, InStr(fileName, "_v") - 1) & "_v" & index & "." & ext
'Debug.Print fileName
Loop
ActiveWorkbook.SaveAs (fileName)
End Sub
答案 7 :(得分:-6)
您应该设置一个条件循环来检查TextBox1值。
If TextBox1.value = "" then
MsgBox "The file not exist"
Exit sub 'exit the macro
End If
希望对你有所帮助。