Question

我有一个页面，我输入参数来查询记录列表。单击查询按钮时，如果单击列表中的项目，则会返回到显示记录的第一页。

当我点击另一个按钮' new '清除页面并返回一个空页面时，网址中有一个参数，它设置页面上项目的值。该项目是网址中有犯罪记录。

如何摆脱这种情况我想要返回一个空页？

方案

我在一个包含以下网址:http://adomain/crimeTrack/crime_registration.htm
我点击查询对另一个显示记录列表的网址执行POST：http://adomain/crimeTrack/crimeList.htm
在上面2中的上一页中，然后选择一条执行POST的记录，并将我带到以下网址：http://adomain/crimeTrack/getCrime/6.htm - where 6 is the crimeRecNo.
我现在在上面的网址上，然后点击“新建”按钮获取一个空白表单，上面的网址为1。当我点击新的时，在

代码示例4中对控制器方法进行了POST
此方法重定向到映射到GET方法的url，但最终的url如下所示：http://adomain/crimeTrack/%20crime_registration.htm?crimeRecNo=6

值6保留在crimeRecNo字段中，并且不会清除整个表单。

Under是控制器方法：

1。初始页面请求

@RequestMapping(value = "crime_registration.htm", method = RequestMethod.GET) public ModelAndView loadPage(HttpServletRequest request,HttpServletResponse response, @ModelAttribute Crime crime,BindingResult result, ModelMap m, Model model, SessionStatus status,HttpSession session) throws Exception { try { logger.debug("In Crime Registration Controller"); myCriminalList.put("dbcriminalList", this.citizenManager.getListOfCriminals()); ................... session.setAttribute("page", 0); return new ModelAndView("crime_registration"); } catch (Exception e) { logger.debug("Exception In CrimeRegistration Controller : " + e.getMessage()); return new ModelAndView("crime_registration"); } }

2。查询物品清单

@RequestMapping(value = "crimeList.htm", method = RequestMethod.POST) public ModelAndView handelCrimeList(@ModelAttribute Crime crime, BindingResult result, ModelMap m, Model model) throws Exception { if (crimeManager.getCrimesList(crime).size() <= 0) { model.addAttribute("dbcriminals", myCriminalList); ........ model.addAttribute("crimeTypeList", crimeTypeManager.getCrimeTypeList(crime.getOffenceCatId())); model.addAttribute("icon", "ui-icon ui-icon-circle-close"); model.addAttribute("results","Error: Query Caused No Records To Be Retrieved!"); return new ModelAndView("crime_registration"); } model.addAttribute("crimes", crimeManager.getCrimesList(crime)); return new ModelAndView("crimeList"); }

第3。申请单项/从列表中选择项目

@RequestMapping(value = "getCrime/{crimeRecNo}.htm", method = RequestMethod.POST) public ModelAndView getCrime(@PathVariable Integer crimeRecNo, @ModelAttribute Crime crime, BindingResult result, ModelMap m, Model model, HttpServletRequest request, HttpServletResponse response, HttpSession session) throws Exception { try { model.addAttribute("crime", crimeManager.getCrimeRecord(crimeRecNo)); session.setAttribute("crimeRecNo", crimeRecNo); //model.addAttribute("victimList", citizenManager.getVictimListByCrimeRecNo(crimeRecNo)); } catch (Exception e) { logger.error("Exception in CitizenRegistrationController - ModelAndView getCitizen " + e); } int crimeCatId = crimeManager.getCrimeRecord(crimeRecNo).getOffenceCatId(); logger.info("crime category number is : "+crimeCatId); myCrimeTypeList.put("crimeTypeList", this.crimeTypeManager.getCrimeTypeList(crimeCatId)); model.addAttribute("dbcriminals", myCriminalList); ..... session.setAttribute("crimeRecNo", crimeRecNo); return new ModelAndView("crime_registration"); }

4。申请新表格

@RequestMapping(value = "crime_registration_new.htm", method = RequestMethod.POST) public String loadNew(HttpServletRequest request,Model model, HttpServletResponse response,SessionStatus status,HttpSession session) throws Exception { status.setComplete(); return "redirect: crime_registration.htm"; //return new ModelAndView(new RedirectView("crime_registration.htm")); }

Answer 1

将此添加到4可以解决问题

@RequestMapping(value = "crime_registration_new.htm", method = RequestMethod.POST)
public String loadNew(HttpServletRequest request,Model model,
        HttpServletResponse response,SessionStatus status,HttpSession session) throws Exception {

    status.setComplete();

  model.addAttribute("crime", new Crime());
    return "redirect: crime_registration.htm";
    //return new ModelAndView(new RedirectView("crime_registration.htm")); 


}

url中的SpringMVC参数问题

1 个答案: